如何使用反应位置延迟加载路线?
How to lazy load route with react location?
我对 React 很陌生,我有一个项目使用 react-location
我想只在路径激活时才延迟加载一些路由。
我当前的配置是:
我的基本路由模块
export const routes: Route[] = [
...HomeModuleRoutes, // I want this to be instantly loaded.
...LazyRoutes, // I want this to be lazy loaded.
{ path: '/', element: <Navigate to="/home" /> },
];
这 2 个常量如下所示:
home.routing.ts
export const routes: Route[] = [
{
path: 'home',
element: <HomeTemplate />,
children: [
{
path: '/',
element: <HomePage />,
},
],
},
];
lazy.routing.ts
export const LazyRoutes: Route[] = [
{
path: 'test',
element: <LazyTemplate />,
children: [
{
path: '/',
element: <LazyList />,
},
{
path: 'add',
element: <LazyAdd />,
},
{
path: 'detail',
element: <LazyDetail />,
},
],
},
];
我不太了解这方面的文档或示例,它只是用 <Suspense>
包装组件吗?
您应该使用 React.lazy
导入您的组件,例如:
const HomeTemplate = React.lazy(() => import("./HomeTemplate "));
检查此示例是否适用于 react-router v6 lazy loading
我对 React 很陌生,我有一个项目使用 react-location
我想只在路径激活时才延迟加载一些路由。
我当前的配置是:
我的基本路由模块
export const routes: Route[] = [
...HomeModuleRoutes, // I want this to be instantly loaded.
...LazyRoutes, // I want this to be lazy loaded.
{ path: '/', element: <Navigate to="/home" /> },
];
这 2 个常量如下所示:
home.routing.ts
export const routes: Route[] = [
{
path: 'home',
element: <HomeTemplate />,
children: [
{
path: '/',
element: <HomePage />,
},
],
},
];
lazy.routing.ts
export const LazyRoutes: Route[] = [
{
path: 'test',
element: <LazyTemplate />,
children: [
{
path: '/',
element: <LazyList />,
},
{
path: 'add',
element: <LazyAdd />,
},
{
path: 'detail',
element: <LazyDetail />,
},
],
},
];
我不太了解这方面的文档或示例,它只是用 <Suspense>
包装组件吗?
您应该使用 React.lazy
导入您的组件,例如:
const HomeTemplate = React.lazy(() => import("./HomeTemplate "));
检查此示例是否适用于 react-router v6 lazy loading