如何解析 url 以获取键和值
How to parse a url to get key and value
我指的是 this 解析 url 的答案,但是当解析这个 url
NSString *urlString = @"https://www.example.com/product-detail?journey_id=123456&iswa=1";
我得到的第一把钥匙是 https://www.example.com/product-detail?journey_id
但我只需要 journey_id
作为我的钥匙。
这是我在编码中所做的:
NSString *urlString = @"https://www.example.com/product-detail?journey_id=123456&iswa=1";
NSMutableDictionary *waLoginDictionary = [[NSMutableDictionary alloc] init];
NSArray *urlComponents = [urlString componentsSeparatedByString:@"&"];
for (NSString *keyValuePair in urlComponents) {
NSArray *pairComponents = [keyValuePair componentsSeparatedByString:@"="];
NSString *key = [[pairComponents firstObject] stringByRemovingPercentEncoding];
NSString *value = [[pairComponents lastObject] stringByRemovingPercentEncoding];
[waLoginDictionary setObject:value forKey:key];
}
NSLog(@"%@", waLoginDictionary);
我得到这个输出:
{
"https://www.example.com/product-detail?journey_id" = 123456;
iswa = 1;
}
您所指的答案已过时,作者本人已相应更新。 Apple 在 URLComponent
对象中添加了 [URLQueryItem]
。
试试这个。
Swift
let urlString = "https://www.example.com/product-detail?journey_id=123456&iswa=1"
var dict: [String : String] = [:]
if let urlComponents = URLComponents(string: urlString), let queryItems = urlComponents.queryItems {
for item in queryItems {
dict[item.name] = item.value
}
}
print("dict : \(dict)")
Objective - C
NSString *urlString = @"https://www.example.com/product-detail?journey_id=123456&iswa=1";
NSMutableDictionary *dict = [NSMutableDictionary dictionary];
NSURLComponents *urlComponents = [NSURLComponents componentsWithString:urlString];
NSArray *queryItems = [urlComponents queryItems];
for (NSURLQueryItem *item in queryItems) {
[dict setValue:item.value forKey:item.name];
}
NSLog(@"dict %@", dict);