从列中的列表中删除方括号
Remove square brackets from lists in a column
我在数据框中有包含列表的列。我只想删除方括号:
| Fruits |
| -------------------------------------|
| [apple, kiwi, pineapple, mango, lime]|
| [strawberry, cherry, kiwi, orange] |
| [...] |
期望的输出:
| Fruits |
| -----------------------------------|
| apple, kiwi, pineapple, mango, lime|
| strawberry, cherry, kiwi, orange |
| ... |
我试过了
for fruit in df['Fruits']:
df['Fruits'] = (','.join(word))
print(df['Fruits'])
输出不是我想要的,如何将新列表附加到新列(当然不需要方括号)谁能帮忙?
您可以尝试使用 replace()
函数将 []
个字符替换为 empty
个字符:
for fruit in df['Fruits']:
df['Fruits'] = df['Fruits'].replace("[", "").replace("]", "")
print(df['Fruits'])
IIUC,试试这个用于字符串存储或列表存储:
# String object
df_string = pd.DataFrame({'Fruits':['[apple, kiwi, pineapple, mango]',
'[strawberry, cherry, kiwi, orange]']})
df_string['Fruits'].str.replace('\[|\]','', regex=True)
输出:
0 apple, kiwi, pineapple, mango
1 strawberry, cherry, kiwi, orange
Name: Fruits, dtype: object
或者,
#List object
df_list = pd.DataFrame({'Fruits':[['apple', 'kiwi', 'pineapple', 'mango'],
['strawberry', 'cherry', 'kiwi', 'orange']]})
df_list['Fruits'].agg(', '.join)
输出:
0 apple, kiwi, pineapple, mango
1 strawberry, cherry, kiwi, orange
Name: Fruits, dtype: object
注意:df_list 和 df_string 字符串表示看起来相同。
print(df_list)
Fruits
0 [apple, kiwi, pineapple, mango]
1 [strawberry, cherry, kiwi, orange]
print(df_string)
Fruits
0 [apple, kiwi, pineapple, mango]
1 [strawberry, cherry, kiwi, orange]
我在数据框中有包含列表的列。我只想删除方括号:
| Fruits |
| -------------------------------------|
| [apple, kiwi, pineapple, mango, lime]|
| [strawberry, cherry, kiwi, orange] |
| [...] |
期望的输出:
| Fruits |
| -----------------------------------|
| apple, kiwi, pineapple, mango, lime|
| strawberry, cherry, kiwi, orange |
| ... |
我试过了
for fruit in df['Fruits']:
df['Fruits'] = (','.join(word))
print(df['Fruits'])
输出不是我想要的,如何将新列表附加到新列(当然不需要方括号)谁能帮忙?
您可以尝试使用 replace()
函数将 []
个字符替换为 empty
个字符:
for fruit in df['Fruits']:
df['Fruits'] = df['Fruits'].replace("[", "").replace("]", "")
print(df['Fruits'])
IIUC,试试这个用于字符串存储或列表存储:
# String object
df_string = pd.DataFrame({'Fruits':['[apple, kiwi, pineapple, mango]',
'[strawberry, cherry, kiwi, orange]']})
df_string['Fruits'].str.replace('\[|\]','', regex=True)
输出:
0 apple, kiwi, pineapple, mango
1 strawberry, cherry, kiwi, orange
Name: Fruits, dtype: object
或者,
#List object
df_list = pd.DataFrame({'Fruits':[['apple', 'kiwi', 'pineapple', 'mango'],
['strawberry', 'cherry', 'kiwi', 'orange']]})
df_list['Fruits'].agg(', '.join)
输出:
0 apple, kiwi, pineapple, mango
1 strawberry, cherry, kiwi, orange
Name: Fruits, dtype: object
注意:df_list 和 df_string 字符串表示看起来相同。
print(df_list)
Fruits
0 [apple, kiwi, pineapple, mango]
1 [strawberry, cherry, kiwi, orange]
print(df_string)
Fruits
0 [apple, kiwi, pineapple, mango]
1 [strawberry, cherry, kiwi, orange]