如何获取SQL服务器程序的返回值？

Question

我正在尝试使用 Laravel 查询生成器执行下面的过程，结果总是空数组，

SQL 程序

CREATE FUNCTION [dbo].[FConvTxtUnt] 
(
    -- Add the parameters for the function here
    @itmid int ,
    @number numeric(12,2) 
)
RETURNS nvarchar(150)
AS
BEGIN
--     
    declare @txtunitqty as nvarchar(150)
    set  @txtunitqty=''

    declare @factors as numeric(12,2)
    declare @result as int
    declare @result2 as numeric(12,2)

    set @result=1
    declare tcur  cursor for 
    select itemunitid,unitname 
    from stock_ItemsUnits
    inner join  stock_Units on stock_Units.unitid=stock_ItemsUnits.unitid 
    where itmid = @itmid 
    order by itemunitid
                
   open tcur ;

   declare @Itemunitid int; 
   declare @unitname nvarchar(50);
   fetch next from tcur into @Itemunitid,@unitname
   while (@@fetch_status = 0)
   BEGIN
      set @factors = (
          select EXP(SUM(LOG(factor)))  
          from  stock_ItemsUnits
          where itmid = @itmid and Itemunitid>=@Itemunitid 
      )
  
      if ( @factors=1)
      begin
         set   @txtunitqty=@txtunitqty +'/'+cast (@number as nvarchar(50))+@unitname
      end
      else
      begin
         set @result= @number/@factors
         set @result2= @number%@factors  
         set   @txtunitqty=@txtunitqty +'/'+cast (@result as nvarchar(50))+@unitname
      end
      set @number=@result2

      fetch next from tcur into @Itemunitid,@unitname;
   end

   close tcur;
   deallocate tcur;

   RETURN @txtunitqty

END

实现代码，

return DB::select("EXEC FConvTxtUnt ?,?", [$itemId ,$quantity] );

结果总是这样，

[]

任何人都可以告诉我哪里出了问题，考虑到我没有修改程序本身的权限，我无法将 return 更改为输出。

Answer 1

我将重点关注问题的 PHP 部分。您正在尝试执行一个函数，而不是一个过程，因此您只需更改语句：

DB::select("SELECT dbo.FConvTxtUnt(?, ?)", [$itemId, $quantity]);

我明白你不能改变功能，因为你...没有权限修改程序...，但你需要考虑非常仔细看关于使用循环和游标的评论。

如何获取SQL服务器程序的返回值？

How to fetch SQL Server procedure returned value?

php

sql-server

query-builder

laravel

eloquent