将数组转换为具有自定义属性的对象
Transform array into object with custom properties
我有这个数组
myarr = [
'=title1',
'longText0...',
'longtText1...',
'=title2',
'longTextA...',
'longtTextB...',
'longtTextC...'
];
符号 =
表示这是一个 属性,旁边是属于 属性
的项目列表
我想将该数组转换为对象
myObj = {
title1: [
'longText0...',
'longtText1...',
],
title2: [
'longTextA...',
'longtTextB...',
'longtTextC...'
]
}
到目前为止我想出了这个代码:
const arrayToObject = (array) =>
array.reduce((obj, item) => {
if(item.startsWith('=')) {
const itemName = item.replace('=', '')
obj[itemName] = itemName;
} else {
//add the rest....
}
return obj
}, {})
console.log(arrayToObject(myarr))
我目前面临的挑战是我不确定如何转向 obj[itemName]
以便我可以将项目分配给它。有什么想法吗?
我不会用 reduce
这样做,而是用一个简单的 for
循环,因为你必须在多次迭代中携带 itemname
let o = {}, n = '';
for (let k of arr) {
if (k.startsWith('=')) {
n = k.substring(1);
o[n] = []
} else {
o[n].push(k);
}
}
你当然也可以用reduce
来做,但是你必须把itemname
的声明放在回调之外
let n = '';
let o = arr.reduce((a, c) => {
if (c.startsWith('=')) {
n = c.substring(1);
a[n] = [];
} else {
a[n].push(c);
}
return a;
}, {});
请注意,没有错误处理,即代码假定您的数组结构良好并且数组中的第一个元素必须以 =
开头
下面的函数会给你想要的结果
function arrayToObject(arr)
{
let returnObj={};
for(let i =0; i <arr.length; i++)
{
if(arr[i].startsWith('='))
{
let itemName = arr[i].replace('=','');
returnObj[itemName]=[];
for(let j=i+1; j <arr.length;j++)
{
if(arr[j].startsWith('='))
{
break;
}
else
{
let value = arr[j];
returnObj[itemName].push(value) ;
}
}
}
}
return returnObj;
}
这里是 reduce
的版本
const myarr = [
'=title1',
'longText0...',
'longtText1...',
'=title2',
'longTextA...',
'longtTextB...',
'longtTextC...'
];
const obj = myarr.reduce((res, el) => {
if(el.startsWith('=')){
const key = el.substring(1)
return {
data: {
...res.data,
[key]: [],
},
key
}
}
return {
...res,
data:{
...res.data,
[res.key]: [...res.data[res.key], el]
}
}
}, {
data: {},
key: ''
}).data
console.log(obj)
一个reduce
based approach which does not depend on outer scope references for keeping track of the currently to be built/aggregated property makes this information part of the reducer function's first parameter, the previousValue
which serves as an accumulator/collector object.
因此,对于 OP 的任务,此收集器将具有两个属性,currentKey
和 result
,其中前者保存当前处理的 属性 名称的状态后者是以编程方式构建的结果。
// - reducer function which aggregates entries at time,
// either by creating a new property or by pushing a
// value into the currently processed property value.
// - keeps the state of the currently processed property
// by the accumulator`s/collector's `currentKey` property
// whereas the result programmatically gets build as
// the accumulator`s/collector's `result` property.
function aggregateEntry({ currentKey = null, result = {} }, item) {
const key = (item.startsWith('=') && item.slice(1));
if (
(key !== false) &&
(key !== currentKey)
) {
// keep track of the currently processed property name.
currentKey = key;
// create a new entry (key value pair).
result[currentKey] = [];
} else {
// push value into the currently processed property value.
result[currentKey].push(item);
}
return { currentKey, result };
}
console.log([
'=title1',
'longText0...',
'longtText1...',
'=title2',
'longTextA...',
'longtTextB...',
'longtTextC...',
].reduce(aggregateEntry, { result: {} }).result);
.as-console-wrapper { min-height: 100%!important; top: 0; }
对于 reduce 方法,您不需要将密钥单独保存在某个地方:
const myarr = ['=title1', 'longText0...', 'longtText1...', '=title2', 'longTextA...', 'longtTextB...', 'longtTextC...'];
const res = Object.fromEntries(
myarr.reduce((acc, item) => {
if(item.startsWith('='))
acc.push([item.substring(1), []]);
else
acc[acc.length - 1]?.[1].push(item);
return acc;
}, [])
);
console.log(JSON.stringify( res ));
我有这个数组
myarr = [
'=title1',
'longText0...',
'longtText1...',
'=title2',
'longTextA...',
'longtTextB...',
'longtTextC...'
];
符号 =
表示这是一个 属性,旁边是属于 属性
我想将该数组转换为对象
myObj = {
title1: [
'longText0...',
'longtText1...',
],
title2: [
'longTextA...',
'longtTextB...',
'longtTextC...'
]
}
到目前为止我想出了这个代码:
const arrayToObject = (array) =>
array.reduce((obj, item) => {
if(item.startsWith('=')) {
const itemName = item.replace('=', '')
obj[itemName] = itemName;
} else {
//add the rest....
}
return obj
}, {})
console.log(arrayToObject(myarr))
我目前面临的挑战是我不确定如何转向 obj[itemName]
以便我可以将项目分配给它。有什么想法吗?
我不会用 reduce
这样做,而是用一个简单的 for
循环,因为你必须在多次迭代中携带 itemname
let o = {}, n = '';
for (let k of arr) {
if (k.startsWith('=')) {
n = k.substring(1);
o[n] = []
} else {
o[n].push(k);
}
}
你当然也可以用reduce
来做,但是你必须把itemname
的声明放在回调之外
let n = '';
let o = arr.reduce((a, c) => {
if (c.startsWith('=')) {
n = c.substring(1);
a[n] = [];
} else {
a[n].push(c);
}
return a;
}, {});
请注意,没有错误处理,即代码假定您的数组结构良好并且数组中的第一个元素必须以 =
下面的函数会给你想要的结果
function arrayToObject(arr)
{
let returnObj={};
for(let i =0; i <arr.length; i++)
{
if(arr[i].startsWith('='))
{
let itemName = arr[i].replace('=','');
returnObj[itemName]=[];
for(let j=i+1; j <arr.length;j++)
{
if(arr[j].startsWith('='))
{
break;
}
else
{
let value = arr[j];
returnObj[itemName].push(value) ;
}
}
}
}
return returnObj;
}
这里是 reduce
const myarr = [
'=title1',
'longText0...',
'longtText1...',
'=title2',
'longTextA...',
'longtTextB...',
'longtTextC...'
];
const obj = myarr.reduce((res, el) => {
if(el.startsWith('=')){
const key = el.substring(1)
return {
data: {
...res.data,
[key]: [],
},
key
}
}
return {
...res,
data:{
...res.data,
[res.key]: [...res.data[res.key], el]
}
}
}, {
data: {},
key: ''
}).data
console.log(obj)
一个reduce
based approach which does not depend on outer scope references for keeping track of the currently to be built/aggregated property makes this information part of the reducer function's first parameter, the previousValue
which serves as an accumulator/collector object.
因此,对于 OP 的任务,此收集器将具有两个属性,currentKey
和 result
,其中前者保存当前处理的 属性 名称的状态后者是以编程方式构建的结果。
// - reducer function which aggregates entries at time,
// either by creating a new property or by pushing a
// value into the currently processed property value.
// - keeps the state of the currently processed property
// by the accumulator`s/collector's `currentKey` property
// whereas the result programmatically gets build as
// the accumulator`s/collector's `result` property.
function aggregateEntry({ currentKey = null, result = {} }, item) {
const key = (item.startsWith('=') && item.slice(1));
if (
(key !== false) &&
(key !== currentKey)
) {
// keep track of the currently processed property name.
currentKey = key;
// create a new entry (key value pair).
result[currentKey] = [];
} else {
// push value into the currently processed property value.
result[currentKey].push(item);
}
return { currentKey, result };
}
console.log([
'=title1',
'longText0...',
'longtText1...',
'=title2',
'longTextA...',
'longtTextB...',
'longtTextC...',
].reduce(aggregateEntry, { result: {} }).result);
.as-console-wrapper { min-height: 100%!important; top: 0; }
对于 reduce 方法,您不需要将密钥单独保存在某个地方:
const myarr = ['=title1', 'longText0...', 'longtText1...', '=title2', 'longTextA...', 'longtTextB...', 'longtTextC...'];
const res = Object.fromEntries(
myarr.reduce((acc, item) => {
if(item.startsWith('='))
acc.push([item.substring(1), []]);
else
acc[acc.length - 1]?.[1].push(item);
return acc;
}, [])
);
console.log(JSON.stringify( res ));