VS 代码 - SonarLint:Simplify 表达式产生无效语法

Question

我收到 S1125 是因为有代码味道：

MyVO vo;
public boolean is() {
    return vo == null ? false : vo.is();
}

Remove the unnecessary boolean literal.sonarlint(java:S1125)

But when choosing Quick Fix -> SonarLint:Simplify the expression it return invalid java syntax:

return !vo == null && vo.is();

是 Sonar Lint 错误吗？是我的 vs code 设置有误吗？

显然它应该固定为：

return vo != null && vo.is();

（使用最新的 VS 代码和 sonar lint 插件）

我在声纳中没有发现任何问题community/Jira

Answer 1

在 Sonar 社区中打开了一个问题 https://community.sonarsource.com/t/sonarlint-simplify-the-expression-wrong-syntax-on-java-s1125/62467

报告为 SONARJAVA-4241

S1125: erroneous quick fix suggestion when negating a binary operation

可能会被删除

It seems that covering all the cases seems tricky. We might want to simplify and simply don't suggest a quick fix if the expression is a binary operation.

VS 代码 - SonarLint:Simplify 表达式产生无效语法

VS code - SonarLint:Simplify the expression produce invalid syntax

java

visual-studio-code

sonarlint