如何遍历 python 中 zip 存档的 zip 存档？

Question

有压缩包 zip.zip 与 zip1.zip 和 zip2.zip 在里面。在 zip1.zip 中是 0.txt，在 zip2.zip 中是 0.txt。总共 O.txt 是字符串“Hello world”。如何遍历 zip.zip 来打印： “你好世界” “你好世界”

我有，但没用：

from zipfile import ZipFile

with ZipFile(zip.zip, 'r') as zipObj:
    listOfFileNames = zipObj.namelist()
    for fileName in listOfFileNames:
        # Check filename endswith csv
        if fileName.endswith('.zip'):
            with ZipFile(fileName) as z:
                txt = z.read('0.txt')
                print (txt)

调试：

with ZipFile(zip.zip, 'r') as zipObj:
File "E:\python\Lib\zipfile.py", line 1265, in __init__
self._RealGetContents()
File "E:\python\Lib\zipfile.py", line 1328, in _RealGetContents
endrec = _EndRecData(fp)
File "E:\python\Lib\zipfile.py", line 264, in _EndRecData
fpin.seek(0, 2)
AttributeError: 'ZipFile' object has no attribute 'seek'

（更新）：

预览调试问题是，在生产项目中，我传递的不是存档 zip.zip，而是 list_of_files，没有指向选择第一个文件 (list_of_files[0]):

with ZipFile(list_of_files[0], 'r') as zipObj:

Answer 1

使用io.BytesIO()

将内容提取到内存

from zipfile import ZipFile
import io

with ZipFile('zip.zip', 'r') as zipObj:
    for fileName in zipObj.namelist():
        if fileName.endswith('.zip'):
            content = io.BytesIO(zipObj.read(fileName)) # zip1.zip
            with ZipFile(content) as z:
                for txt in z.namelist():
                    if txt.endswith('.txt'):
                        txt = z.read('0.txt')
                        print (txt)

如何遍历 python 中 zip 存档的 zip 存档？

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