有没有办法获取这些数据，旋转它然后将它组合成一个字符串..？

Question

我有一个 table，其中包含如下数据：


+=========+============+=========+==============+
|   num   |  module-id | page-no |    txt       |
+=========+============+=========+==============+
| 3177564 |      1     |    1    |text string 1 |
+---------+------------+---------+--------------+
| 3177564 |      1     |    2    |text string 2 |
+---------+------------+---------+--------------+
| 3177564 |      1     |    3    |text string 3 |
+---------+------------+---------+--------------+
| 3177564 |      2     |    1    |text string 1 |
+---------+------------+---------+--------------+
| 3177564 |      2     |    2    |text string 2 |
+---------+------------+---------+--------------+
| 3177564 |      3     |    1    |text string 1 |
+---------+------------+---------+--------------+
| 3177564 |      3     |    2    |text string 2 |
+---------+------------+---------+--------------+
| 3177564 |      3     |    3    |text string 3 |
+---------+------------+---------+--------------+

然后我可以使用 PIVOT 函数生成以下内容：


+=========+============+==============+==============+==============+
|   num   |  module-id | page-no-1    | page-no-2    | page-no-3    | 
+=========+============+==============+==============+==============+
| 3177564 |      1     |text string 1 |text string 2 |text string 3 |
+---------+------------+--------------+--------------+--------------+
| 3177564 |      2     |text string 1 |text string 2 |NULL          |
+---------+------------+--------------+--------------+--------------+
| 3177564 |      3     |text string 1 |text string2  |text string 3 |
+---------+------------+--------------+--------------+--------------+

用于生成枢轴的代码是：

SELECT *
FROM
(
SELECT
j.num
,jpad.[module-id]
,jpad.[page-no]
,jpad.txt
FROM
job j
LEFT OUTER JOIN jobpad jpad ON jpad.num = j.num

WHERE
(j.num IN
('3177564'))
AND (jpad.[page-no] IN (1,2,3,4,5,6,7,8,9,10)) a
PIVOT
(
MAX(a.txt) FOR a.[page-no] IN ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10])
) p
ORDER BY num

这很好，但是我想做的是尽可能按照以下示例连接数据：

请注意 p-1、p-2 等指的是页码。


+=========+=========================================================+=============+=============+
|   num   |                        module-id-1                      | module-id-2 | module-id-3 |
+=========+=========================================================+=============+=============+
| 3177564 |p-1 text string 1 & p-2 text string 2 & p-3 text string 3|per module 1 |per module 1 |
+---------+---------------------------------------------------------+-------------+-------------+

我已经考虑了一段时间了，但脑子里想不出来。

我目前使用 SQL Server 2014。

Answer 1

要获取您要查找的第一列：

; -- see sqlblog.org/cte
WITH src AS
(
  SELECT num, [module-id], txt = STUFF(
    (SELECT CONCAT(' & ', 'p-', [page-no], ' ', txt)
      FROM dbo.StuffAndThings WHERE num = s.num
      AND [module-id] = s.[module-id]
      FOR XML PATH(''), 
      TYPE).value(N'./text()[1]', N'varchar(max)'), 1, 3, '')
  FROM dbo.StuffAndThings AS s
  WHERE [page-no] = 1
)
SELECT num, 
  [module-id-1] = [1], 
  [module-id-2] = [2], 
  [module-id-3] = [3] 
FROM src PIVOT
(MAX(txt) FOR [module-id] IN ([1],[2],[3])) AS p;

示例db<>fiddle

有没有办法获取这些数据，旋转它然后将它组合成一个字符串..？

Is there a way to take this data, pivot it and then combine it into a single string..?

sql

sql-server

sql-server-2014