二维数组平均和总c++
2d array average and total c++
它必须如下所示:
#include <iostream>
using namespace std;
int main()
{
float allsales[3] [2] = {{1200.33, 2350.75}, {3677.80, 2456.05}, {750.67, 1345.99}};
float totalsales = 0, ave = 0, sum = 0;
for (int row = 0; row < 3; row++)
{
cout << "Ave sale for store "<< row + 1 << ": ";
for (int col=0; col < 2; col++)
{
totalsales += allsales [row] [col];
sum = 0; // I cant figure out how to code the formula for the sum
ave = sum / 2;
cout << ave <<endl;
}
}
cout << "Total sales : $" << totalsales << endl;
return 0;
}
此外,我是一名一年级学生,所以我不能使用一些高级 codes/commands 等。我只能坚持嵌套 for 循环,否则,while
float allsales[3] [2] = {{1200.33, 2350.75}, {3677.80, 2456.05}, {750.67, 1345.99}};
float totalsales = 0, ave = 0, sum = 0;
for (int row = 0; row < 3; row++)
{
cout << "Ave sale for store "<< row + 1 << ": ";
sum = 0;
for (int col=0; col < 2; col++)
{
totalsales += allsales[row][col];
sum += allsales[row][col];
}
ave = sum / 2;
cout << ave <<endl;
}
cout << "Total sales : $" << totalsales << endl;
return 0;
sum 和 totalsales 的唯一区别是 sum 一次只针对一行,因此需要在第二次循环开始之前将其初始化为零。在内循环之后还需要计算平均值,一旦计算完一行总和。
尝试干运行代码以更好地理解循环
你会怎么做?
I 将开始 sum
每行的初始值为零,向其添加该行中的每个元素,然后在最后计算平均值该行。
(别忘了您可以在函数中第一处以外的其他地方声明变量。)
我也可能会先对行求和,然后将“行总和”加到总数中。
像这样:
for (int row = 0; row < 3; row++)
{
float sum = 0;
for (int col = 0; col < 2; col++)
{
sum += allsales[row][col];
}
cout << "Ave sale for store "<< row + 1 << ": " << sum / 2 << endl;
totalsales += sum;
}
它必须如下所示:
#include <iostream>
using namespace std;
int main()
{
float allsales[3] [2] = {{1200.33, 2350.75}, {3677.80, 2456.05}, {750.67, 1345.99}};
float totalsales = 0, ave = 0, sum = 0;
for (int row = 0; row < 3; row++)
{
cout << "Ave sale for store "<< row + 1 << ": ";
for (int col=0; col < 2; col++)
{
totalsales += allsales [row] [col];
sum = 0; // I cant figure out how to code the formula for the sum
ave = sum / 2;
cout << ave <<endl;
}
}
cout << "Total sales : $" << totalsales << endl;
return 0;
}
此外,我是一名一年级学生,所以我不能使用一些高级 codes/commands 等。我只能坚持嵌套 for 循环,否则,while
float allsales[3] [2] = {{1200.33, 2350.75}, {3677.80, 2456.05}, {750.67, 1345.99}};
float totalsales = 0, ave = 0, sum = 0;
for (int row = 0; row < 3; row++)
{
cout << "Ave sale for store "<< row + 1 << ": ";
sum = 0;
for (int col=0; col < 2; col++)
{
totalsales += allsales[row][col];
sum += allsales[row][col];
}
ave = sum / 2;
cout << ave <<endl;
}
cout << "Total sales : $" << totalsales << endl;
return 0;
sum 和 totalsales 的唯一区别是 sum 一次只针对一行,因此需要在第二次循环开始之前将其初始化为零。在内循环之后还需要计算平均值,一旦计算完一行总和。
尝试干运行代码以更好地理解循环
你会怎么做?
I 将开始 sum
每行的初始值为零,向其添加该行中的每个元素,然后在最后计算平均值该行。
(别忘了您可以在函数中第一处以外的其他地方声明变量。)
我也可能会先对行求和,然后将“行总和”加到总数中。
像这样:
for (int row = 0; row < 3; row++)
{
float sum = 0;
for (int col = 0; col < 2; col++)
{
sum += allsales[row][col];
}
cout << "Ave sale for store "<< row + 1 << ": " << sum / 2 << endl;
totalsales += sum;
}