如何根据 fetch 数组执行 sql 代码

Question

我有一个在 google 上找到的搜索引擎，我想在我拥有的 'barcode' 数据库中搜索，如果它找到人，它会执行 $ 下的代码语句（我在 $statement 下添加了我发现的代码中未包含的代码），我对信息的回显不感兴趣，这就是为什么我删除了那部分并进行了刷新，我只会有兴趣执行 sql 中的更改，一旦找到您要找的人，就不必是下面这样的代码，我真的不知道该怎么做，我在这里寻求帮助。

<?php
    include 'includes/conn.php';
    include 'includes/scripts.php'; 


    if (isset($_POST['no'])) {
        $sca=trim($_POST['no'],""); 
        $credentials="";
        $new2 ="SELECT * FROM `barcode`";
        $mysqli = new $conn;
        $statement= $mysqli->prepare("Insert IGNORE into voters
                                    Select * from barcode where id = id;
                                    DELETE from barcode where id IN(SELECT id from voters)");
        $res2=mysqli_query($conn, $new2);
        while($row=mysqli_fetch_array($res2)){
           if($row['credentials'] == $sca){
              $statement->execute();
              header("refresh: .5");
           }       
        }
    }
    $statement->close();
    mysqli_close($conn);
 
?>

Answer 1

不清楚你的插入逻辑是什么以及你到底想插入什么，但让我告诉你我将如何构造这样一个查询（包括一些安全措施，如准备好的语句），希望你可以改变 SQL 语句根据你的需要。我在大多数行上留下了评论来解释

<?php
    include 'includes/conn.php';
    include 'includes/scripts.php'; 


    if (isset($_POST['no'])) {
        $sca=trim($_POST['no'],""); 
        $credentials="";
        $sql = "SELECT * FROM `barcode`";
        $mysqli = new $conn;
        // Prepare the statement
        $stmt = $mysqli->prepare($sql);
        // Attempt to execute
        if ($stmt->execute()) {
            // Save result
            $result = $stmt->get_result();
            // save the result in an assoc array
            $row = $result->fetch_all(MYSQL_ASSOC);
                // If there is a returned entry
                if (count($row) > 0) {
                    if ($row['credentials'] === $sca) {
                        // close the statement so we can re-use
                        $stmt->close();
                        // We assume id is what we need
                        $id = $row['id'];
                        // Now you have to fix your INSERT statement here. I am not sure what you need to insert but follow the general docs on how to insert https://www.php.net/manual/en/mysqli-stmt.bind-param.php
                        $stmt = $mysqli->prepare("INSERT IGNORE INTO `voters` (columnName) VALUES (?)");
                        // Here you need to decide what you are inserting and change the variable
                        $stmt->bind_param("s", $whatever_variable_you_insert);
                        // Attempt to execute
                        if ($stmt->execute()) {
                            // if successful, proceed with the deletion too... or you can put it outside this execute condition
                            $stmt->close();
                            // Prepare the delete statement
                            $stmt = $mysqli->prepare("DELETE FROM `barcode` WHERE id=?");
                            // Bind the param
                            $stmt->bind_para("s", $id);
                            if ($stmt->exceute()) {
                                // something else or as you wanted - refresh
                                header("refresh: .5");
                            }
                        }
                    }
                }
        }
    }
?>

Answer 2

这是存储过程的理想情况。我假设你尝试你的逻辑似乎是：

查找条形码（通过 id 和 sca？）
如果找到条形码，请插入投票器table
从条码中删除条码table

所以像

create procedure `check_barcode` (sca int)
begin
    select * into result from `code` where id = sca limit 1;
    if not result is null then
        insert into `voters` select * from `barcode` where id = sca;
        delete from `barcode` where id = sca;
    end if;
end

您没有包含 table 设计，这有点猜测。

Answer 3

我找到了我要找的东西！

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>Document</title>
    <?php
        include "includes/scripts.php";
    ?>
</head>
<body>
    <div class="container mt-5 pt-5">
        <form id="scanform"  autocomplete="off" method="POST">
            <div class="row">
                <div class="col-sm-3">
                    <h1>Scan:</h1>
                </div>
                <div class="col-sm-6">
                    <div class="form-group">
                        <input type="text" id="no" name="no" class="form-control" required>
                    </div>
                </div>
                <div class="col-sm-3">
                    <button class="btn btn-info" name="sub" type="submit">Buscar</button>
                </div>
            </div>
        </form>
    </div>
</body>
</html>
<?php
    include 'includes/conn.php';

    if (isset($_POST['no'])) {
        $sca = trim($_POST['no'],"");
        $flag = 0;
        $id= "";
        $credentials = "";
        $password = "";
        $firstname = "";
        $lastname = "";
        $sql = "SELECT * FROM `barcode` WHERE credentials = '" . $sca . "' LIMIT 1";

        $result = mysqli_query($conn , $sql);

        $barcode = mysqli_fetch_assoc($result);
        if ($barcode) {
            $mod = "INSERT IGNORE INTO voters
                    Select * from barcode where id = " . $barcode['id'];
            $insert_result = mysqli_query($conn , $mod);

            if ($insert_result) {
                $del = "DELETE from barcode where id = " . $barcode['id'];
                $del_result = mysqli_query($conn , $del);

                echo "<div class='alert alert-success d-flex justify-content-center mt-3'>Product has been removed from barcode!</div></div>";
            } else {
                echo "<div class='alert alert-danger d-flex justify-content-center mt-3'>Something went wrong while deleting from barcode!</div></div>";
            }
        } else {
            echo "<div class='alert alert-danger d-flex justify-content-center mt-3'>Product Not Found</div></div>";
            return;
        }
    }
    mysqli_close($conn);
?>

如何根据 fetch 数组执行 sql 代码

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