如何在每次按下按钮时增加 5 秒，在 micropython 中打开 LED

Question

你能帮帮我吗：我想通过按下一个按钮来打开 LED，它应该保持打开状态 5 秒钟，但我希望它，如果我在它打开时按下按钮，只要时间加起来它就会保持打开状态。例如：当 LED 亮起并且我再次按下按钮时，它将亮起 10 秒钟。我正在使用 raspberry pi pico 和 Thonny

这是我的代码：

from machine import Pin, Timer
import time

White_LED = Pin(15, Pin.OUT)

button = Pin(14, Pin.IN, Pin.PULL_DOWN) 



while True:
    if button.value() == 1:
        White_LED.on() 
        time.sleep(5) 
        White_LED.off()

Answer 1

在你休眠5秒的那一刻，代码停止。因此，如果您再次按下按钮，它不会注意到。

我认为您需要使用中断处理程序 (https://docs.micropython.org/en/v1.8.6/pyboard/reference/isr_rules.html)，或者您可以自己实现一个简单的事件循环。

事件循环不断寻找发生的事情，并在发生时执行某些操作。这是您可能如何做的粗略想法。

from machine import Pin, Timer
import time

White_LED = Pin(15, Pin.OUT)

button = Pin(14, Pin.IN, Pin.PULL_DOWN)

button_was = 0
light_on_until = 0

while True:
    # See if the state of the button has changed
    button_now = button.value()
    if button_now != button_was:
        button_was = button_now 
        if button_now == 1:
            # button is down, but it was up. 
            # Increase light on time by 5 seconds
            if light_on_until > time.ticks_ms():
                # light is already on, increase the time by 5,000 ms
                light_on_until += 5000
            else:
                # light isn't on, so set time to 5 seconds from now (5,000 ms)
                light_on_until = time.ticks_ms() + 5000

    if light_on_until > time.ticks_ms():
        # light should be on, so if it's currently off, switch it on        
        if White_LED.value() == 0:
            White_LED.on()
    else:
        # light should be off, so if it's currently on, switch it off
        if White_LED.value() == 1:
            White_LED.off()

如何在每次按下按钮时增加 5 秒，在 micropython 中打开 LED

How to make an LED on, in micropython by adding 5 seconds each time you press a push button

python

micropython

raspberry-pi-pico