jq select 路径子集 selected

Question

我得到的多个路径数组包含以下关键字 'headline'：

jq -c 'paths | select(.[-1] == "headline")' nytimeseuro.json
["data","legacyCollection","collectionsPage","stream","edges",0,"node","headline"]
["data","legacyCollection","collectionsPage","stream","edges",1,"node","headline"]
["data","legacyCollection","collectionsPage","stream","edges",2,"node","headline"]
["data","legacyCollection","collectionsPage","stream","edges",3,"node","headline"]
["data","legacyCollection","collectionsPage","stream","edges",4,"node","headline"]
["data","legacyCollection","headline"]

我可以 select 它们基于数组索引吗？就像输出[0:2] select 只是

["data","legacyCollection","collectionsPage","stream","edges",0,"node","headline"]
["data","legacyCollection","collectionsPage","stream","edges",1,"node","headline"]
["data","legacyCollection","collectionsPage","stream","edges",2,"node","headline"]

或输出[-1] select只是

["data","legacyCollection","headline"]

我尝试了下面的命令，但这似乎不是我想要的，它只是将我得到的 每个路径 切片，而不是 select 所有路径的子集 返回：

jq -c 'paths | select(.[-1] == "headline")[:3]' nytimeseuro.json
["data","legacyCollection","collectionsPage"]
["data","legacyCollection","collectionsPage"]
["data","legacyCollection","collectionsPage"]
["data","legacyCollection","collectionsPage"]
["data","legacyCollection","collectionsPage"]
["data","legacyCollection","headline"]

Answer 1

paths 生成一个流，而您显然想要一个数组，您可以从中轻松提取感兴趣的项目。例如：

[paths | select(.[-1] == "headline")][0:2]

Stream-oriented 替代品也可用，例如限制（2；路径....）

jq select 路径子集 selected

jq select a subset of paths selected

bash

json

jq