如何从颤动中的选定文本字段值中删除特定字母

Question

所以我有这个带有控制器的文本字段，我能够获得突出显示的选定值并毫无问题地更改它。

CustomTextField(
  hintText: "Write something...",
  maxLines: null,
  controller: _controller,
  addBorder: false,
),

//Lets say the text inside the textfield is "Good morning my friends"

CustomButton(
    text: "Change",
    onClick: () {
      //This is to get the highlighted/selected text inside the textfield (Lets say it's "morning")
      String highlightedText = _controller.selection.textInside(_controller.text);

      //This is to get all the text before the highlighted text = "Good "
      String textBefore = _controller.selection.textBefore(_controller.text);

      //This is to get all the text after the highlighted text = " my friends"
      String textAfter = _controller.selection.textAfter(_controller.text);

      //This is to change or modify the highlighted text = "**morning**"
      String changeSelectedText = "**$selectedText**";

      //This is to join the before and after text and add to back to the controller = "Good **morning** my friends"
      String newText = textBefore + changeSelectedText + textAfter;
      
      print(newText);
      _controller.text = newText;
      
    }),

现在我的问题是如何首先检查“morning”是否已经被“**morning**”包围。因为我用过这个

if (textAfter.contains("**") || textBefore.contains("**")) {
   textAfter = textAfter.replaceAll("**", "");
   textBefore = textBefore.replaceAll("**", "");
}

但它会检查文本字段中的每个词是否 ** 不是我选择的词。所以请问我该怎么做，比如正则表达式或使用它 positions

Answer 1

改用endsWith和startsWith：

if (textAfter.startsWith("**") || textBefore.endsWith("**")) {
  // Don't replace all ** with empty text, just make a substring and cut them off
  // textAfter = textAfter.replaceAll("**", "");
  // textBefore = textBefore.replaceAll("**", "");

  textAfter = textAfter.substring(2);
  textBefore = textBefore.replaceAll(0, textBefore.length - 2);
}

如何从颤动中的选定文本字段值中删除特定字母

How to remove specific letters from a selected textfield value in flutter

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flutter