我正在尝试连接 2 个没有相同列并使用 case select 的表。这可能吗？
I'm trying to join 2 tables that don't have same columns and using case select. Is this possible?
select
case
when code = number_1
then number_1=code
when count(code)>=count(number_1)
then number_1 = sum(code)
else 'Null'
end
from table_1, table_2
ORDER BY code, number_1 ;
table 1
code
value
0
None
1
R
2
W
4
C
8
D
16
U
32
Uown
Table 2
number
0
1
2
3
4
5
8
12
13
16
20
25
26
27
32
43
44
45
60
61
62
63
64
68
70
预期输出是
number
output
0
0
1
1
2
2
3
2,1
4
4
7
4,2,1
8
8
16
16
32
32
43
32,8,2,1
63
32,16,8,4,2,1
64
null
70
null
可以在JOIN条件下使用BITAND函数：
SELECT t2."NUMBER",
CASE SUM(t1.code)
WHEN t2."NUMBER"
THEN LISTAGG(t1.code, ',') WITHIN GROUP (ORDER BY t1.code DESC)
END AS output,
CASE SUM(t1.code)
WHEN t2."NUMBER"
THEN LISTAGG(t1.value, ',') WITHIN GROUP (ORDER BY t1.code DESC)
END AS value_output
FROM table_2 t2
INNER JOIN table_1 t1
ON ( t2."NUMBER" = t1.code
OR (t1.code > 0 AND BITAND(t2."NUMBER", t1.code) = t1.code))
GROUP BY t2."NUMBER"
其中，对于示例数据：
CREATE TABLE table_1 (code, value) AS
SELECT 0, 'None' FROM DUAL UNION ALL
SELECT 1, 'R' FROM DUAL UNION ALL
SELECT 2, 'W' FROM DUAL UNION ALL
SELECT 4, 'C' FROM DUAL UNION ALL
SELECT 8, 'D' FROM DUAL UNION ALL
SELECT 16, 'U' FROM DUAL UNION ALL
SELECT 32, 'Uown' FROM DUAL;
CREATE TABLE Table_2 ("NUMBER") AS
SELECT COLUMN_VALUE
FROM SYS.ODCINUMBERLIST(
0,1,2,3,4,5,8,12,13,16,20,25,26,27,32,43,44,45,60,61,62,63,64,68,70
);
输出：
NUMBER
OUTPUT
VALUE_OUTPUT
0
0
None
1
1
R
2
2
W
3
2,1
W,R
4
4
C
5
4,1
C,R
8
8
D
12
8,4
D,C
13
8,4,1
D,C,R
16
16
U
20
16,4
U,C
25
16,8,1
U,D,R
26
16,8,2
U,D,W
27
16,8,2,1
U,D,W,R
32
32
Uown
43
32,8,2,1
Uown,D,W,R
44
32,8,4
Uown,D,C
45
32,8,4,1
Uown,D,C,R
60
32,16,8,4
Uown,U,D,C
61
32,16,8,4,1
Uown,U,D,C,R
62
32,16,8,4,2
Uown,U,D,C,W
63
32,16,8,4,2,1
Uown,U,D,C,W,R
68
null
null
70
null
null
db<>fiddle here
select
case
when code = number_1
then number_1=code
when count(code)>=count(number_1)
then number_1 = sum(code)
else 'Null'
end
from table_1, table_2
ORDER BY code, number_1 ;
table 1
| code | value |
|---|---|
| 0 | None |
| 1 | R |
| 2 | W |
| 4 | C |
| 8 | D |
| 16 | U |
| 32 | Uown |
Table 2
| number |
|---|
| 0 |
| 1 |
| 2 |
| 3 |
| 4 |
| 5 |
| 8 |
| 12 |
| 13 |
| 16 |
| 20 |
| 25 |
| 26 |
| 27 |
| 32 |
| 43 |
| 44 |
| 45 |
| 60 |
| 61 |
| 62 |
| 63 |
| 64 |
| 68 |
| 70 |
预期输出是
| number | output |
|---|---|
| 0 | 0 |
| 1 | 1 |
| 2 | 2 |
| 3 | 2,1 |
| 4 | 4 |
| 7 | 4,2,1 |
| 8 | 8 |
| 16 | 16 |
| 32 | 32 |
| 43 | 32,8,2,1 |
| 63 | 32,16,8,4,2,1 |
| 64 | null |
| 70 | null |
可以在JOIN条件下使用BITAND函数：
SELECT t2."NUMBER",
CASE SUM(t1.code)
WHEN t2."NUMBER"
THEN LISTAGG(t1.code, ',') WITHIN GROUP (ORDER BY t1.code DESC)
END AS output,
CASE SUM(t1.code)
WHEN t2."NUMBER"
THEN LISTAGG(t1.value, ',') WITHIN GROUP (ORDER BY t1.code DESC)
END AS value_output
FROM table_2 t2
INNER JOIN table_1 t1
ON ( t2."NUMBER" = t1.code
OR (t1.code > 0 AND BITAND(t2."NUMBER", t1.code) = t1.code))
GROUP BY t2."NUMBER"
其中，对于示例数据：
CREATE TABLE table_1 (code, value) AS
SELECT 0, 'None' FROM DUAL UNION ALL
SELECT 1, 'R' FROM DUAL UNION ALL
SELECT 2, 'W' FROM DUAL UNION ALL
SELECT 4, 'C' FROM DUAL UNION ALL
SELECT 8, 'D' FROM DUAL UNION ALL
SELECT 16, 'U' FROM DUAL UNION ALL
SELECT 32, 'Uown' FROM DUAL;
CREATE TABLE Table_2 ("NUMBER") AS
SELECT COLUMN_VALUE
FROM SYS.ODCINUMBERLIST(
0,1,2,3,4,5,8,12,13,16,20,25,26,27,32,43,44,45,60,61,62,63,64,68,70
);
输出：
NUMBER OUTPUT VALUE_OUTPUT 0 0 None 1 1 R 2 2 W 3 2,1 W,R 4 4 C 5 4,1 C,R 8 8 D 12 8,4 D,C 13 8,4,1 D,C,R 16 16 U 20 16,4 U,C 25 16,8,1 U,D,R 26 16,8,2 U,D,W 27 16,8,2,1 U,D,W,R 32 32 Uown 43 32,8,2,1 Uown,D,W,R 44 32,8,4 Uown,D,C 45 32,8,4,1 Uown,D,C,R 60 32,16,8,4 Uown,U,D,C 61 32,16,8,4,1 Uown,U,D,C,R 62 32,16,8,4,2 Uown,U,D,C,W 63 32,16,8,4,2,1 Uown,U,D,C,W,R 68 null null 70 null null
db<>fiddle here