正则表达式通过布尔运算符拆分布尔字符串

Question

是否有正则表达式通过布尔运算符拆分布尔字符串但不在引号内

示例： boolean_string = "'larsen and turbo' and fullsta'ck or \"ruby\" and \"ruby or rails\""

预期输出： ['larsen and turbo', and, fullsta'ck, or, ruby, and, ruby or rails]

目前正在尝试使用以下代码片段，但无法在引号内转义运算符。 boolean_string.split(/\b(and|or)\b/)

如何在引号内转义 and 和 or's。`

Answer 1

这可能对您有帮助：

boolean_string = "'larsen and turbo' and fullsta'ck or \"ruby\" and \"ruby or rails\""
reg = %r{
  (?:                # outer-group to use "|" for multiple matches
    ['"]([^'"]+)['"] # words inside quotes
    |([\w']+)        # other words
  )
}xm

boolean_string.scan(reg).flat_map(&:compact) # => ["larsen and turbo", "and", "fullsta'ck", "or", "ruby", "and", "ruby or rails"]

正则表达式通过布尔运算符拆分布尔字符串

Regex split boolean string by boolean operators

ruby-on-rails

regex

ruby