'QuerySet' 对象没有属性 '_meta',Django 有 ajax

'QuerySet' object has no attribute '_meta', Django with ajax

我正在为一家纹身店建立网站。在我的 index 视图中,我首先显示每位艺术家的所有纹身,但我试图让用户按艺术家过滤纹身,然后使用 jquery/ajax.[=26= 更新显示所选艺术家纹身的页面]

ArtistTattoo 型号:

class Artist(models.Model):
    first_name  = models.CharField(max_length=50)
    last_name  = models.CharField(max_length=50)
    # etc

class Tattoo(models.Model):
    artist = models.ForeignKey(Artist, on_delete=models.CASCADE)
    name  = models.CharField(max_length=150)
    image = models.ImageField(upload_to='images/')
    date_created = models.DateTimeField(auto_now_add=True)

forms.py:

class FilterArtForm(ModelForm):
    class Meta:
        model = Tattoo
        fields = ['artist']

        widgets = {
            'artist': forms.Select(attrs={'id': 'filter_by_artist'}),
        }

views.py:

def index(request):
    tattoos = Tattoo.objects.order_by('-date_created')
    filter_art_form = FilterArtForm()
    artist_id = request.GET.get('artist')
    if artist_id:
        artist = Artist.objects.get(pk = artist_id)
        tattoos = tattoos.filter(artist=artist) # trying to return this as a JsonResponse is causing some kind of issue
        return JsonResponse({'tattoos': model_to_dict(tattoos)}, status=200)
    return render(request, 'core/index.html', {'tattoos':tattoos, 'filter_art_form': filter_art_form})

我是使用 ajax 的新手,所以我只是在摆弄我的观点,如果我尝试 return 只有 Artist 对象本身:

 def index(request):
        tattoos = Tattoo.objects.order_by('-date_created')
        filter_art_form = FilterArtForm()
        artist_id = request.GET.get('artist')
        if artist_id:
            artist = Artist.objects.get(pk = artist_id)
            return JsonResponse({'artist': model_to_dict(artist)}, status=200)
        return render(request, 'core/index.html', {'tattoos':tattoos, 'filter_art_form': filter_art_form})

这会起作用,我会得到以下响应:

{"artist": {"id": 1, "first_name": "First", "last_name": "Last"}}

但是当我尝试检索与上述 Artist 相关联的 Tattoo 对象时,我得到了这个 'QuerySet' object has no attribute '_meta' 错误。我认为这与 Tattoo 模型的 ImageField 有关,或者与 returning 多个对象而不只是一个对象的事实有关,但我不确定。感谢您对此的任何帮助。

这样试试

if artist_id:
   tattoos = tattoos.filter(artist__id=artist_id).values()
   return JsonResponse({'tattoos_by_artist': list(tattoos)}, status=200)