如何根据数据类型创建一个在每个索引中都有一个字符串的数组？
How to create an array that has in each index a string depending on the data type?
我有一个数组，其中嵌套了一个对象。我正在尝试使用 map() 创建一个数组，每个索引中都有字符串 "war" 或 "peace"。如果 name 属性 同时具有 cat 和 dog，则字符串“war”。 "peace" 否则。到目前为止，我已经尝试过使用嵌套的 for in 循环来访问 pets 对象中的嵌套对象。但我无法让它检查所有 name 属性。这是我的代码。
const data = [
{
name: 'mark',
age: 27,
from: "Chicago",
pets: []
}, {
name: 'greg',
age: 68,
from: "Auburn",
pets: [{
type: "rock",
name: "herbert",
age: 126003219
}]
}, {
name: 'ken',
age: 28,
from: "Naperville",
pets: [{
type: "cat",
name: "colby",
age: 1
}, {
type: "dog",
name: "charlie",
age: 3
}, {
type: "dog",
name: "william riker",
age: 1
}, {
type: "dog",
name: "thomas riker",
age: 1
}]
}, {
name: 'kristiana',
age: 47,
from: "Chicago",
pets: []
}, {
name: 'bryan',
age: 27,
from: "Lincoln Park Zoo",
pets: [{
type: "white tiger",
name: "arthur",
age: 3
}, {
type: "silverback gorilla",
name: "tommy",
age: 4
}, {
type: "guinea pig",
name: "kirk",
age: 1
}, {
type: "hamster",
name: "spock",
age: 1
}, {
type: "hamster",
name: "sarek",
age: 1
}, {
type: "cat",
name: "quark",
age: 1
}, {
type: "cat",
name: "kira nerys",
age: 1
}]
}, {
name: 'anthony',
age: 31,
from: "Phoenix",
pets: []
}, {
name: 'stephanie',
age: 27,
from: "Chicago",
pets: [{
type: "dog",
name: "midnight",
age: 3
}]
}, {
name: 'david p',
age: 40,
from: "Lancaster",
pets: [{
type: "dog",
name: "quinn",
age: 8
}]
}, {
name: 'patrick',
age: 39,
from: "Poway",
pets: [{
type: "dog",
name: "hazel",
age: 7
}, {
type: "cat",
name: "fredy perlman",
age: 13
}]
}, {
name: 'david a',
age: 32,
from: "San Francisco",
pets: [{
type: "monstera",
name: "holey",
age: 1
}]
}, {
name: 'timm',
age: 32,
from: "Gainsville",
pets: [{
type: "goldfish",
name: "betsy",
age: 4
}]
}, {
name: 'conrad',
age: 101,
from: "Minneapolis",
pets: []
}, {
name: 'nate',
age: 14,
from: "Boston",
pets: [{
type: "cat",
name: "rosie",
age: 0.005
}, {
type: "hermit crab",
name: "kermit",
age: 1 // 16 wow wtf
}, {
type: "dog",
name: "ernie",
age: 4
}, {
type: "cat",
name: "kendrick lamar jr",
age: 6
}, {
type: "cat",
name: "guinan",
age: 589
}, {
type: "cat",
name: "beverly",
age: 1
}]
}, {
name: 'temo',
age: 25,
from: "Osaka",
pets: [{
type: "dog",
name: "nacho",
age: 1
}, {
type: "dog",
name: "belky",
age: 1
}, {
type: "dog",
name: "janeway",
age: 4
}, {
type: "dog",
name: "jean-luc",
age: 12
}, {
type: "monkey",
name: "shin chan",
age: 1
}]
}, {
name: 'griffin',
age: 22,
from: "Chicago",
pets: [{
type: "bearded dragon",
name: "ferg",
age: 3
}]
}, {
name: 'eman',
age: 20,
from: "Lake in the Hills",
pets: [{
type: "parakeet",
name: "sunny",
age: 400
}, {
type: "parrot",
name: "vic fontaine",
age: 46
}, {
type: "parrot",
name: "worf",
age: 48
}, {
type: "cockatoo",
name: "spockatoo",
age: 33
}]
}, {
name: 'jürgen',
age: 28,
from: "Chicago",
pets: [{
type: "cat",
name: "mija",
age: 6
}]
}, {
name: 'michele',
age: 33,
from: "Rome",
pets: [{
type: "cat",
name: "caesar", // "cheeto"
age: 3
}, {
type: "cat",
name: "cleopatra",
age: 3
}, {
type: "cat",
name: "tuvok",
age: 10
}, {
type: "turtle",
name: "spock",
age: 13
}]
}, {
name: 'mitchell',
age: 19,
from: "Iowa City",
pets: [{
type: "cat",
name: "eddie",
age: 7
}]
}, {
name: 'reuben',
age: 41,
from: "Durham",
pets: [{
type: "cat",
name: "nico",
age: 15
}, {
type: "cat",
name: "rocky",
age: 5
}]
}, {
name: 'fatima',
age: 24,
from: "Milwaukee",
pets: [{
type: "snake",
name: "reginald",
age: 12
}]
}
]
const warAndPeace = data.map(sadPeople => {
for (keys in sadPeople) {
for (key in sadPeople) {
if (sadPeople['pets'].type === 'dog ' && sadPeople === 'cat') {
console.log('War');
} else {
console.log('peace');
}
}
}
});
console.log(warAndPeace);
我认为您想要做的是检查宠物列表，看它是否包含任何给定人的“狗”类型和“猫”类型。在这种情况下，您可以做的是将每个人的宠物类型映射到 Set（以获取唯一宠物类型列表），然后检查该 Set 是否包含 both “猫”和“狗”。如果是，return“war”，如果不是，return“和平”。这是一个例子：
const data = [ { name: 'mark', age: 27, from: "Chicago", pets: [] }, { name: 'greg', age: 68, from: "Auburn", pets: [{ type: "rock", name: "herbert", age: 126003219 }] }, { name: 'ken', age: 28, from: "Naperville", pets: [{ type: "cat", name: "colby", age: 1 }, { type: "dog", name: "charlie", age: 3 }, { type: "dog", name: "william riker", age: 1 }, { type: "dog", name: "thomas riker", age: 1 }] }, { name: 'kristiana', age: 47, from: "Chicago", pets: [] }, { name: 'bryan', age: 27, from: "Lincoln Park Zoo", pets: [{ type: "white tiger", name: "arthur", age: 3 }, { type: "silverback gorilla", name: "tommy", age: 4 }, { type: "guinea pig", name: "kirk", age: 1 }, { type: "hamster", name: "spock", age: 1 }, { type: "hamster", name: "sarek", age: 1 }, { type: "cat", name: "quark", age: 1 }, { type: "cat", name: "kira nerys", age: 1 }] }, { name: 'anthony', age: 31, from: "Phoenix", pets: [] }, { name: 'stephanie', age: 27, from: "Chicago", pets: [{ type: "dog", name: "midnight", age: 3 }] }, { name: 'david p', age: 40, from: "Lancaster", pets: [{ type: "dog", name: "quinn", age: 8 }] }, { name: 'patrick', age: 39, from: "Poway", pets: [{ type: "dog", name: "hazel", age: 7 }, { type: "cat", name: "fredy perlman", age: 13 }] }, { name: 'david a', age: 32, from: "San Francisco", pets: [{ type: "monstera", name: "holey", age: 1 }] }, { name: 'timm', age: 32, from: "Gainsville", pets: [{ type: "goldfish", name: "betsy", age: 4 }] }, { name: 'conrad', age: 101, from: "Minneapolis", pets: [] }, { name: 'nate', age: 14, from: "Boston", pets: [{ type: "cat", name: "rosie", age: 0.005 }, { type: "hermit crab", name: "kermit", age: 1 }, { type: "dog", name: "ernie", age: 4 }, { type: "cat", name: "kendrick lamar jr", age: 6 }, { type: "cat", name: "guinan", age: 589 }, { type: "cat", name: "beverly", age: 1 }] }, { name: 'temo', age: 25, from: "Osaka", pets: [{ type: "dog", name: "nacho", age: 1 }, { type: "dog", name: "belky", age: 1 }, { type: "dog", name: "janeway", age: 4 }, { type: "dog", name: "jean-luc", age: 12 }, { type: "monkey", name: "shin chan", age: 1 }] }, { name: 'griffin', age: 22, from: "Chicago", pets: [{ type: "bearded dragon", name: "ferg", age: 3 }] }, { name: 'eman', age: 20, from: "Lake in the Hills", pets: [{ type: "parakeet", name: "sunny", age: 400 }, { type: "parrot", name: "vic fontaine", age: 46 }, { type: "parrot", name: "worf", age: 48 }, { type: "cockatoo", name: "spockatoo", age: 33 }] }, { name: 'jürgen', age: 28, from: "Chicago", pets: [{ type: "cat", name: "mija", age: 6 }] }, { name: 'michele', age: 33, from: "Rome", pets: [{ type: "cat", name: "caesar", age: 3 }, { type: "cat", name: "cleopatra", age: 3 }, { type: "cat", name: "tuvok", age: 10 }, { type: "turtle", name: "spock", age: 13 }] }, { name: 'mitchell', age: 19, from: "Iowa City", pets: [{ type: "cat", name: "eddie", age: 7 }] }, { name: 'reuben', age: 41, from: "Durham", pets: [{ type: "cat", name: "nico", age: 15 }, { type: "cat", name: "rocky", age: 5 }] }, { name: 'fatima', age: 24, from: "Milwaukee", pets: [{ type: "snake", name: "reginald", age: 12 }] } ]
let warAndPeace = data.map(person => {
let petTypes = new Set(person.pets.map(pet => pet.type));
if (petTypes.has('dog') && petTypes.has('cat')) {
return 'war'
}
return 'peace'
});
console.log(warAndPeace);
一种方法是映射 data 数组，使用 array.some() 方法检查 pets 数组是否同时具有 cat 和 dog 类型, 和 return war 或 peace 相应地:
let result = data.map(i =>
i.pets.some(p => p.type === 'cat') && i.pets.some(p => p.type === 'dog') ? 'war' : 'peace'
)
console.log(result)
<script>
const data = [
{
name: 'mark',
age: 27,
from: "Chicago",
pets: []
}, {
name: 'greg',
age: 68,
from: "Auburn",
pets: [{
type: "rock",
name: "herbert",
age: 126003219
}]
}, {
name: 'ken',
age: 28,
from: "Naperville",
pets: [{
type: "cat",
name: "colby",
age: 1
}, {
type: "dog",
name: "charlie",
age: 3
}, {
type: "dog",
name: "william riker",
age: 1
}, {
type: "dog",
name: "thomas riker",
age: 1
}]
}, {
name: 'kristiana',
age: 47,
from: "Chicago",
pets: []
}, {
name: 'bryan',
age: 27,
from: "Lincoln Park Zoo",
pets: [{
type: "white tiger",
name: "arthur",
age: 3
}, {
type: "silverback gorilla",
name: "tommy",
age: 4
}, {
type: "guinea pig",
name: "kirk",
age: 1
}, {
type: "hamster",
name: "spock",
age: 1
}, {
type: "hamster",
name: "sarek",
age: 1
}, {
type: "cat",
name: "quark",
age: 1
}, {
type: "cat",
name: "kira nerys",
age: 1
}]
}, {
name: 'anthony',
age: 31,
from: "Phoenix",
pets: []
}, {
name: 'stephanie',
age: 27,
from: "Chicago",
pets: [{
type: "dog",
name: "midnight",
age: 3
}]
}, {
name: 'david p',
age: 40,
from: "Lancaster",
pets: [{
type: "dog",
name: "quinn",
age: 8
}]
}, {
name: 'patrick',
age: 39,
from: "Poway",
pets: [{
type: "dog",
name: "hazel",
age: 7
}, {
type: "cat",
name: "fredy perlman",
age: 13
}]
}, {
name: 'david a',
age: 32,
from: "San Francisco",
pets: [{
type: "monstera",
name: "holey",
age: 1
}]
}, {
name: 'timm',
age: 32,
from: "Gainsville",
pets: [{
type: "goldfish",
name: "betsy",
age: 4
}]
}, {
name: 'conrad',
age: 101,
from: "Minneapolis",
pets: []
}, {
name: 'nate',
age: 14,
from: "Boston",
pets: [{
type: "cat",
name: "rosie",
age: 0.005
}, {
type: "hermit crab",
name: "kermit",
age: 1 // 16 wow wtf
}, {
type: "dog",
name: "ernie",
age: 4
}, {
type: "cat",
name: "kendrick lamar jr",
age: 6
}, {
type: "cat",
name: "guinan",
age: 589
}, {
type: "cat",
name: "beverly",
age: 1
}]
}, {
name: 'temo',
age: 25,
from: "Osaka",
pets: [{
type: "dog",
name: "nacho",
age: 1
}, {
type: "dog",
name: "belky",
age: 1
}, {
type: "dog",
name: "janeway",
age: 4
}, {
type: "dog",
name: "jean-luc",
age: 12
}, {
type: "monkey",
name: "shin chan",
age: 1
}]
}, {
name: 'griffin',
age: 22,
from: "Chicago",
pets: [{
type: "bearded dragon",
name: "ferg",
age: 3
}]
}, {
name: 'eman',
age: 20,
from: "Lake in the Hills",
pets: [{
type: "parakeet",
name: "sunny",
age: 400
}, {
type: "parrot",
name: "vic fontaine",
age: 46
}, {
type: "parrot",
name: "worf",
age: 48
}, {
type: "cockatoo",
name: "spockatoo",
age: 33
}]
}, {
name: 'jürgen',
age: 28,
from: "Chicago",
pets: [{
type: "cat",
name: "mija",
age: 6
}]
}, {
name: 'michele',
age: 33,
from: "Rome",
pets: [{
type: "cat",
name: "caesar", // "cheeto"
age: 3
}, {
type: "cat",
name: "cleopatra",
age: 3
}, {
type: "cat",
name: "tuvok",
age: 10
}, {
type: "turtle",
name: "spock",
age: 13
}]
}, {
name: 'mitchell',
age: 19,
from: "Iowa City",
pets: [{
type: "cat",
name: "eddie",
age: 7
}]
}, {
name: 'reuben',
age: 41,
from: "Durham",
pets: [{
type: "cat",
name: "nico",
age: 15
}, {
type: "cat",
name: "rocky",
age: 5
}]
}, {
name: 'fatima',
age: 24,
from: "Milwaukee",
pets: [{
type: "snake",
name: "reginald",
age: 12
}]
}
]
</script>
我有一个数组，其中嵌套了一个对象。我正在尝试使用 map() 创建一个数组，每个索引中都有字符串 "war" 或 "peace"。如果 name 属性 同时具有 cat 和 dog，则字符串“war”。 "peace" 否则。到目前为止，我已经尝试过使用嵌套的 for in 循环来访问 pets 对象中的嵌套对象。但我无法让它检查所有 name 属性。这是我的代码。
const data = [
{
name: 'mark',
age: 27,
from: "Chicago",
pets: []
}, {
name: 'greg',
age: 68,
from: "Auburn",
pets: [{
type: "rock",
name: "herbert",
age: 126003219
}]
}, {
name: 'ken',
age: 28,
from: "Naperville",
pets: [{
type: "cat",
name: "colby",
age: 1
}, {
type: "dog",
name: "charlie",
age: 3
}, {
type: "dog",
name: "william riker",
age: 1
}, {
type: "dog",
name: "thomas riker",
age: 1
}]
}, {
name: 'kristiana',
age: 47,
from: "Chicago",
pets: []
}, {
name: 'bryan',
age: 27,
from: "Lincoln Park Zoo",
pets: [{
type: "white tiger",
name: "arthur",
age: 3
}, {
type: "silverback gorilla",
name: "tommy",
age: 4
}, {
type: "guinea pig",
name: "kirk",
age: 1
}, {
type: "hamster",
name: "spock",
age: 1
}, {
type: "hamster",
name: "sarek",
age: 1
}, {
type: "cat",
name: "quark",
age: 1
}, {
type: "cat",
name: "kira nerys",
age: 1
}]
}, {
name: 'anthony',
age: 31,
from: "Phoenix",
pets: []
}, {
name: 'stephanie',
age: 27,
from: "Chicago",
pets: [{
type: "dog",
name: "midnight",
age: 3
}]
}, {
name: 'david p',
age: 40,
from: "Lancaster",
pets: [{
type: "dog",
name: "quinn",
age: 8
}]
}, {
name: 'patrick',
age: 39,
from: "Poway",
pets: [{
type: "dog",
name: "hazel",
age: 7
}, {
type: "cat",
name: "fredy perlman",
age: 13
}]
}, {
name: 'david a',
age: 32,
from: "San Francisco",
pets: [{
type: "monstera",
name: "holey",
age: 1
}]
}, {
name: 'timm',
age: 32,
from: "Gainsville",
pets: [{
type: "goldfish",
name: "betsy",
age: 4
}]
}, {
name: 'conrad',
age: 101,
from: "Minneapolis",
pets: []
}, {
name: 'nate',
age: 14,
from: "Boston",
pets: [{
type: "cat",
name: "rosie",
age: 0.005
}, {
type: "hermit crab",
name: "kermit",
age: 1 // 16 wow wtf
}, {
type: "dog",
name: "ernie",
age: 4
}, {
type: "cat",
name: "kendrick lamar jr",
age: 6
}, {
type: "cat",
name: "guinan",
age: 589
}, {
type: "cat",
name: "beverly",
age: 1
}]
}, {
name: 'temo',
age: 25,
from: "Osaka",
pets: [{
type: "dog",
name: "nacho",
age: 1
}, {
type: "dog",
name: "belky",
age: 1
}, {
type: "dog",
name: "janeway",
age: 4
}, {
type: "dog",
name: "jean-luc",
age: 12
}, {
type: "monkey",
name: "shin chan",
age: 1
}]
}, {
name: 'griffin',
age: 22,
from: "Chicago",
pets: [{
type: "bearded dragon",
name: "ferg",
age: 3
}]
}, {
name: 'eman',
age: 20,
from: "Lake in the Hills",
pets: [{
type: "parakeet",
name: "sunny",
age: 400
}, {
type: "parrot",
name: "vic fontaine",
age: 46
}, {
type: "parrot",
name: "worf",
age: 48
}, {
type: "cockatoo",
name: "spockatoo",
age: 33
}]
}, {
name: 'jürgen',
age: 28,
from: "Chicago",
pets: [{
type: "cat",
name: "mija",
age: 6
}]
}, {
name: 'michele',
age: 33,
from: "Rome",
pets: [{
type: "cat",
name: "caesar", // "cheeto"
age: 3
}, {
type: "cat",
name: "cleopatra",
age: 3
}, {
type: "cat",
name: "tuvok",
age: 10
}, {
type: "turtle",
name: "spock",
age: 13
}]
}, {
name: 'mitchell',
age: 19,
from: "Iowa City",
pets: [{
type: "cat",
name: "eddie",
age: 7
}]
}, {
name: 'reuben',
age: 41,
from: "Durham",
pets: [{
type: "cat",
name: "nico",
age: 15
}, {
type: "cat",
name: "rocky",
age: 5
}]
}, {
name: 'fatima',
age: 24,
from: "Milwaukee",
pets: [{
type: "snake",
name: "reginald",
age: 12
}]
}
]
const warAndPeace = data.map(sadPeople => {
for (keys in sadPeople) {
for (key in sadPeople) {
if (sadPeople['pets'].type === 'dog ' && sadPeople === 'cat') {
console.log('War');
} else {
console.log('peace');
}
}
}
});
console.log(warAndPeace);
我认为您想要做的是检查宠物列表，看它是否包含任何给定人的“狗”类型和“猫”类型。在这种情况下，您可以做的是将每个人的宠物类型映射到 Set（以获取唯一宠物类型列表），然后检查该 Set 是否包含 both “猫”和“狗”。如果是，return“war”，如果不是，return“和平”。这是一个例子：
const data = [ { name: 'mark', age: 27, from: "Chicago", pets: [] }, { name: 'greg', age: 68, from: "Auburn", pets: [{ type: "rock", name: "herbert", age: 126003219 }] }, { name: 'ken', age: 28, from: "Naperville", pets: [{ type: "cat", name: "colby", age: 1 }, { type: "dog", name: "charlie", age: 3 }, { type: "dog", name: "william riker", age: 1 }, { type: "dog", name: "thomas riker", age: 1 }] }, { name: 'kristiana', age: 47, from: "Chicago", pets: [] }, { name: 'bryan', age: 27, from: "Lincoln Park Zoo", pets: [{ type: "white tiger", name: "arthur", age: 3 }, { type: "silverback gorilla", name: "tommy", age: 4 }, { type: "guinea pig", name: "kirk", age: 1 }, { type: "hamster", name: "spock", age: 1 }, { type: "hamster", name: "sarek", age: 1 }, { type: "cat", name: "quark", age: 1 }, { type: "cat", name: "kira nerys", age: 1 }] }, { name: 'anthony', age: 31, from: "Phoenix", pets: [] }, { name: 'stephanie', age: 27, from: "Chicago", pets: [{ type: "dog", name: "midnight", age: 3 }] }, { name: 'david p', age: 40, from: "Lancaster", pets: [{ type: "dog", name: "quinn", age: 8 }] }, { name: 'patrick', age: 39, from: "Poway", pets: [{ type: "dog", name: "hazel", age: 7 }, { type: "cat", name: "fredy perlman", age: 13 }] }, { name: 'david a', age: 32, from: "San Francisco", pets: [{ type: "monstera", name: "holey", age: 1 }] }, { name: 'timm', age: 32, from: "Gainsville", pets: [{ type: "goldfish", name: "betsy", age: 4 }] }, { name: 'conrad', age: 101, from: "Minneapolis", pets: [] }, { name: 'nate', age: 14, from: "Boston", pets: [{ type: "cat", name: "rosie", age: 0.005 }, { type: "hermit crab", name: "kermit", age: 1 }, { type: "dog", name: "ernie", age: 4 }, { type: "cat", name: "kendrick lamar jr", age: 6 }, { type: "cat", name: "guinan", age: 589 }, { type: "cat", name: "beverly", age: 1 }] }, { name: 'temo', age: 25, from: "Osaka", pets: [{ type: "dog", name: "nacho", age: 1 }, { type: "dog", name: "belky", age: 1 }, { type: "dog", name: "janeway", age: 4 }, { type: "dog", name: "jean-luc", age: 12 }, { type: "monkey", name: "shin chan", age: 1 }] }, { name: 'griffin', age: 22, from: "Chicago", pets: [{ type: "bearded dragon", name: "ferg", age: 3 }] }, { name: 'eman', age: 20, from: "Lake in the Hills", pets: [{ type: "parakeet", name: "sunny", age: 400 }, { type: "parrot", name: "vic fontaine", age: 46 }, { type: "parrot", name: "worf", age: 48 }, { type: "cockatoo", name: "spockatoo", age: 33 }] }, { name: 'jürgen', age: 28, from: "Chicago", pets: [{ type: "cat", name: "mija", age: 6 }] }, { name: 'michele', age: 33, from: "Rome", pets: [{ type: "cat", name: "caesar", age: 3 }, { type: "cat", name: "cleopatra", age: 3 }, { type: "cat", name: "tuvok", age: 10 }, { type: "turtle", name: "spock", age: 13 }] }, { name: 'mitchell', age: 19, from: "Iowa City", pets: [{ type: "cat", name: "eddie", age: 7 }] }, { name: 'reuben', age: 41, from: "Durham", pets: [{ type: "cat", name: "nico", age: 15 }, { type: "cat", name: "rocky", age: 5 }] }, { name: 'fatima', age: 24, from: "Milwaukee", pets: [{ type: "snake", name: "reginald", age: 12 }] } ]
let warAndPeace = data.map(person => {
let petTypes = new Set(person.pets.map(pet => pet.type));
if (petTypes.has('dog') && petTypes.has('cat')) {
return 'war'
}
return 'peace'
});
console.log(warAndPeace);
一种方法是映射 data 数组，使用 array.some() 方法检查 pets 数组是否同时具有 cat 和 dog 类型, 和 return war 或 peace 相应地:
let result = data.map(i =>
i.pets.some(p => p.type === 'cat') && i.pets.some(p => p.type === 'dog') ? 'war' : 'peace'
)
console.log(result)
<script>
const data = [
{
name: 'mark',
age: 27,
from: "Chicago",
pets: []
}, {
name: 'greg',
age: 68,
from: "Auburn",
pets: [{
type: "rock",
name: "herbert",
age: 126003219
}]
}, {
name: 'ken',
age: 28,
from: "Naperville",
pets: [{
type: "cat",
name: "colby",
age: 1
}, {
type: "dog",
name: "charlie",
age: 3
}, {
type: "dog",
name: "william riker",
age: 1
}, {
type: "dog",
name: "thomas riker",
age: 1
}]
}, {
name: 'kristiana',
age: 47,
from: "Chicago",
pets: []
}, {
name: 'bryan',
age: 27,
from: "Lincoln Park Zoo",
pets: [{
type: "white tiger",
name: "arthur",
age: 3
}, {
type: "silverback gorilla",
name: "tommy",
age: 4
}, {
type: "guinea pig",
name: "kirk",
age: 1
}, {
type: "hamster",
name: "spock",
age: 1
}, {
type: "hamster",
name: "sarek",
age: 1
}, {
type: "cat",
name: "quark",
age: 1
}, {
type: "cat",
name: "kira nerys",
age: 1
}]
}, {
name: 'anthony',
age: 31,
from: "Phoenix",
pets: []
}, {
name: 'stephanie',
age: 27,
from: "Chicago",
pets: [{
type: "dog",
name: "midnight",
age: 3
}]
}, {
name: 'david p',
age: 40,
from: "Lancaster",
pets: [{
type: "dog",
name: "quinn",
age: 8
}]
}, {
name: 'patrick',
age: 39,
from: "Poway",
pets: [{
type: "dog",
name: "hazel",
age: 7
}, {
type: "cat",
name: "fredy perlman",
age: 13
}]
}, {
name: 'david a',
age: 32,
from: "San Francisco",
pets: [{
type: "monstera",
name: "holey",
age: 1
}]
}, {
name: 'timm',
age: 32,
from: "Gainsville",
pets: [{
type: "goldfish",
name: "betsy",
age: 4
}]
}, {
name: 'conrad',
age: 101,
from: "Minneapolis",
pets: []
}, {
name: 'nate',
age: 14,
from: "Boston",
pets: [{
type: "cat",
name: "rosie",
age: 0.005
}, {
type: "hermit crab",
name: "kermit",
age: 1 // 16 wow wtf
}, {
type: "dog",
name: "ernie",
age: 4
}, {
type: "cat",
name: "kendrick lamar jr",
age: 6
}, {
type: "cat",
name: "guinan",
age: 589
}, {
type: "cat",
name: "beverly",
age: 1
}]
}, {
name: 'temo',
age: 25,
from: "Osaka",
pets: [{
type: "dog",
name: "nacho",
age: 1
}, {
type: "dog",
name: "belky",
age: 1
}, {
type: "dog",
name: "janeway",
age: 4
}, {
type: "dog",
name: "jean-luc",
age: 12
}, {
type: "monkey",
name: "shin chan",
age: 1
}]
}, {
name: 'griffin',
age: 22,
from: "Chicago",
pets: [{
type: "bearded dragon",
name: "ferg",
age: 3
}]
}, {
name: 'eman',
age: 20,
from: "Lake in the Hills",
pets: [{
type: "parakeet",
name: "sunny",
age: 400
}, {
type: "parrot",
name: "vic fontaine",
age: 46
}, {
type: "parrot",
name: "worf",
age: 48
}, {
type: "cockatoo",
name: "spockatoo",
age: 33
}]
}, {
name: 'jürgen',
age: 28,
from: "Chicago",
pets: [{
type: "cat",
name: "mija",
age: 6
}]
}, {
name: 'michele',
age: 33,
from: "Rome",
pets: [{
type: "cat",
name: "caesar", // "cheeto"
age: 3
}, {
type: "cat",
name: "cleopatra",
age: 3
}, {
type: "cat",
name: "tuvok",
age: 10
}, {
type: "turtle",
name: "spock",
age: 13
}]
}, {
name: 'mitchell',
age: 19,
from: "Iowa City",
pets: [{
type: "cat",
name: "eddie",
age: 7
}]
}, {
name: 'reuben',
age: 41,
from: "Durham",
pets: [{
type: "cat",
name: "nico",
age: 15
}, {
type: "cat",
name: "rocky",
age: 5
}]
}, {
name: 'fatima',
age: 24,
from: "Milwaukee",
pets: [{
type: "snake",
name: "reginald",
age: 12
}]
}
]
</script>