使用 awk 跳过输入文件的第一行
skip the first line of input file with awk
我正在尝试使用此脚本从一些输入文件中提取数据。问题是输入文件的第一行有一个 header 并且这一行也出现在结果中。该脚本执行它应该执行的操作。如何跳过输入文件的第一行？
#!/bin/awk -f
NF == 3 { ## 3-fields - heading row
if (FNR>1) ## not 1st row
print "" ## output newline
printf "%d", ++n ## output counter 1, 2, 3, ...
for (i=1; i<=NF; i++) ## loop over each heading
printf " %s", $i ## output with 2-leading spaces
next ## skip to next record
}
{
printf "%s", [=10=] ## output all recs until next heading
}
END {
print "" ## END rule - tidy up with newline.
}
我试过这个：
#!/bin/awk -f
NR>1{
NF == 3 { ## 3-fields - heading row
if (FNR>1) ## not 1st row
print "" ## output newline
printf "%d", ++n ## output counter 1, 2, 3, ...
for (i=1; i<=NF; i++) ## loop over each heading
printf " %s", $i ## output with 2-leading spaces
next ## skip to next record
}
{
printf "%s", [=11=] ## output all recs until next heading
}
}
END {
print "" ## END rule - tidy up with newline.
}
但这不是正确的语法。
输入示例如下：
&plot nbnd= 60, nks= 93 /
0.000000 0.000000 0.000000
-44.871 -44.869 -21.466 -21.462 -21.364 -21.275 -21.275 -21.271 -6.942 -6.316
-5.786 -5.623 -5.519 -5.488 -4.009 -3.947 -3.935 -3.935 -3.927 -3.886
-3.822 -3.723 -3.691 -3.661 4.013 5.337 6.511 7.180 7.181 7.730
7.755 7.826 8.312 8.450 8.932 8.932 9.076 9.157 9.397 9.542
9.633 9.909 9.909 11.553 13.243 14.431 14.431 14.547 14.566 14.914
15.137 16.017 16.135 16.410 17.399 17.960 18.076 18.319 19.480 19.480
0.000000 0.100000 0.000000
-44.871 -44.869 -21.466 -21.462 -21.364 -21.277 -21.275 -21.273 -6.928 -6.303
-5.783 -5.621 -5.517 -5.492 -4.007 -3.940 -3.938 -3.934 -3.928 -3.888
-3.820 -3.721 -3.690 -3.659 3.993 5.281 6.513 7.189 7.191 7.645
7.766 7.901 8.255 8.447 8.922 8.934 9.017 9.216 9.401 9.543
9.674 9.869 9.915 11.517 13.293 14.377 14.421 14.434 14.706 14.913
15.138 16.093 16.158 16.424 17.461 17.957 18.043 18.282 19.271 19.450
0.000000 0.200000 0.000000
-44.871 -44.869 -21.466 -21.461 -21.363 -21.283 -21.280 -21.274 -6.888 -6.266
-5.773 -5.613 -5.510 -5.505 -4.001 -3.947 -3.934 -3.929 -3.920 -3.892
-3.816 -3.714 -3.685 -3.654 3.933 5.132 6.519 7.210 7.222 7.539
7.761 7.991 8.095 8.443 8.879 8.937 8.941 9.377 9.402 9.539
如果输入保存在input.dat我运行awk脚本如下：
./script.awk input.dat > output.dat
我一直在阅读 awk 的文档，但我只是不理解这些脚本的结构（如上面的脚本）。他们看起来真的和
不一样
BEGIN {
}
{
}
END {
}
结构。我对 awk 很迷茫，我知道我的问题很烦人...
skip the first line of input file with awk
首先使用 FNR==1{next} pattern-action，将其应用于您的第一个代码会得到
#!/bin/awk -f
FNR==1{next}
NF == 3 { ## 3-fields - heading row
print "" ## output newline
printf "%d", ++n ## output counter 1, 2, 3, ...
for (i=1; i<=NF; i++) ## loop over each heading
printf " %s", $i ## output with 2-leading spaces
next ## skip to next record
}
{
printf "%s", [=10=] ## output all recs until next heading
}
END {
print "" ## END rule - tidy up with newline.
}
我正在尝试使用此脚本从一些输入文件中提取数据。问题是输入文件的第一行有一个 header 并且这一行也出现在结果中。该脚本执行它应该执行的操作。如何跳过输入文件的第一行？
#!/bin/awk -f
NF == 3 { ## 3-fields - heading row
if (FNR>1) ## not 1st row
print "" ## output newline
printf "%d", ++n ## output counter 1, 2, 3, ...
for (i=1; i<=NF; i++) ## loop over each heading
printf " %s", $i ## output with 2-leading spaces
next ## skip to next record
}
{
printf "%s", [=10=] ## output all recs until next heading
}
END {
print "" ## END rule - tidy up with newline.
}
我试过这个：
#!/bin/awk -f
NR>1{
NF == 3 { ## 3-fields - heading row
if (FNR>1) ## not 1st row
print "" ## output newline
printf "%d", ++n ## output counter 1, 2, 3, ...
for (i=1; i<=NF; i++) ## loop over each heading
printf " %s", $i ## output with 2-leading spaces
next ## skip to next record
}
{
printf "%s", [=11=] ## output all recs until next heading
}
}
END {
print "" ## END rule - tidy up with newline.
}
但这不是正确的语法。
输入示例如下：
&plot nbnd= 60, nks= 93 /
0.000000 0.000000 0.000000
-44.871 -44.869 -21.466 -21.462 -21.364 -21.275 -21.275 -21.271 -6.942 -6.316
-5.786 -5.623 -5.519 -5.488 -4.009 -3.947 -3.935 -3.935 -3.927 -3.886
-3.822 -3.723 -3.691 -3.661 4.013 5.337 6.511 7.180 7.181 7.730
7.755 7.826 8.312 8.450 8.932 8.932 9.076 9.157 9.397 9.542
9.633 9.909 9.909 11.553 13.243 14.431 14.431 14.547 14.566 14.914
15.137 16.017 16.135 16.410 17.399 17.960 18.076 18.319 19.480 19.480
0.000000 0.100000 0.000000
-44.871 -44.869 -21.466 -21.462 -21.364 -21.277 -21.275 -21.273 -6.928 -6.303
-5.783 -5.621 -5.517 -5.492 -4.007 -3.940 -3.938 -3.934 -3.928 -3.888
-3.820 -3.721 -3.690 -3.659 3.993 5.281 6.513 7.189 7.191 7.645
7.766 7.901 8.255 8.447 8.922 8.934 9.017 9.216 9.401 9.543
9.674 9.869 9.915 11.517 13.293 14.377 14.421 14.434 14.706 14.913
15.138 16.093 16.158 16.424 17.461 17.957 18.043 18.282 19.271 19.450
0.000000 0.200000 0.000000
-44.871 -44.869 -21.466 -21.461 -21.363 -21.283 -21.280 -21.274 -6.888 -6.266
-5.773 -5.613 -5.510 -5.505 -4.001 -3.947 -3.934 -3.929 -3.920 -3.892
-3.816 -3.714 -3.685 -3.654 3.933 5.132 6.519 7.210 7.222 7.539
7.761 7.991 8.095 8.443 8.879 8.937 8.941 9.377 9.402 9.539
如果输入保存在input.dat我运行awk脚本如下：
./script.awk input.dat > output.dat
我一直在阅读 awk 的文档，但我只是不理解这些脚本的结构（如上面的脚本）。他们看起来真的和
不一样BEGIN {
}
{
}
END {
}
结构。我对 awk 很迷茫，我知道我的问题很烦人...
skip the first line of input file with awk
首先使用 FNR==1{next} pattern-action，将其应用于您的第一个代码会得到
#!/bin/awk -f
FNR==1{next}
NF == 3 { ## 3-fields - heading row
print "" ## output newline
printf "%d", ++n ## output counter 1, 2, 3, ...
for (i=1; i<=NF; i++) ## loop over each heading
printf " %s", $i ## output with 2-leading spaces
next ## skip to next record
}
{
printf "%s", [=10=] ## output all recs until next heading
}
END {
print "" ## END rule - tidy up with newline.
}