如何根据分组条件创建列？
How to create a column based on grouped condition?
我在 powerbi 中的测试表：
IdRecord
Date
Value
1
2022-04-25 23:45:00.000
100
1
2022-04-24 18:07:00.000
344
2
2022-05-01 23:45:00.000
5
2
2022-05-02 18:07:00.000
66
2
2022-05-03 18:07:00.000
31
我需要创建一个计算列来标记最早的按 id 分组的记录。
期望的输出
IdRecord
Date
Value
IsFirst
1
2022-04-25 23:45:00.000
100
0
1
2022-04-24 18:07:00.000
344
1
2
2022-05-01 23:45:00.000
5
1
2
2022-05-02 18:07:00.000
66
0
2
2022-05-03 18:07:00.000
31
0
对自己的回答
FirstRes= VAR MYMIN = CALCULATE(
MIN(Table[Date]),
FILTER ( Table, Table[IdRecord] = EARLIER(Table[IdRecord]))
)
RETURN
IF(CALCULATE(
MIN(MIN(Table[Date]),MYMIN),
FILTER ( Table, Table[IdRecord] = EARLIER ( Table[IdRecord] ) )
) = Table[Date],1,0)
我在 powerbi 中的测试表：
| IdRecord | Date | Value |
|---|---|---|
| 1 | 2022-04-25 23:45:00.000 | 100 |
| 1 | 2022-04-24 18:07:00.000 | 344 |
| 2 | 2022-05-01 23:45:00.000 | 5 |
| 2 | 2022-05-02 18:07:00.000 | 66 |
| 2 | 2022-05-03 18:07:00.000 | 31 |
我需要创建一个计算列来标记最早的按 id 分组的记录。
期望的输出
| IdRecord | Date | Value | IsFirst |
|---|---|---|---|
| 1 | 2022-04-25 23:45:00.000 | 100 | 0 |
| 1 | 2022-04-24 18:07:00.000 | 344 | 1 |
| 2 | 2022-05-01 23:45:00.000 | 5 | 1 |
| 2 | 2022-05-02 18:07:00.000 | 66 | 0 |
| 2 | 2022-05-03 18:07:00.000 | 31 | 0 |
对自己的回答
FirstRes= VAR MYMIN = CALCULATE(
MIN(Table[Date]),
FILTER ( Table, Table[IdRecord] = EARLIER(Table[IdRecord]))
)
RETURN
IF(CALCULATE(
MIN(MIN(Table[Date]),MYMIN),
FILTER ( Table, Table[IdRecord] = EARLIER ( Table[IdRecord] ) )
) = Table[Date],1,0)