在 swift 中检索与正则表达式匹配的子字符串数组

Retrieve array of substring matched with regex in swift

有没有办法在字符串中检索以@符号为前缀的单词数组?

"@City == xyz AND @Hobby == gardening" -> ["@City","@Hobby"]

我尝试了以下两种方法,但都返回一个空数组。

let regexp = "/@\w*/g"

func matches(for regex: String, in text: String) -> [String] {
    do {
        let regex = try NSRegularExpression(pattern: regex)
        let results = regex.matches(in: text,range: NSRange(text.startIndex..., in: text))
        return results.map {
            String(text[Range([=11=].range, in: text)!])
        }
    } catch let error {
        print("invalid regex: \(error.localizedDescription)")
        return []
    }
}

extension String {
    func regex (pattern: String) -> [String] {
        do {
            let regex = try NSRegularExpression(pattern: pattern, options: NSRegularExpression.Options(rawValue: 0))
            let nsstr = self as NSString
            let all = NSRange(location: 0, length: nsstr.length)
            var matches : [String] = [String]()
            regex.enumerateMatches(in: self, options: NSRegularExpression.MatchingOptions(rawValue: 0), range: all) {
                (result : NSTextCheckingResult?, _, _) in
                if let r = result {
                    let result = nsstr.substring(with: r.range) as String
                    matches.append(result)
                }
            }
            return matches
        } catch {
            return [String]()
        }
    }
}

正如@jnpdx 在评论中暗示的那样,您的根本问题是您的 regexp 字符串包含来自另一种语言的控制元素。以下应该可以解决您的问题:

let regexp = "@\w*"

您还会陷入不必要的 try-catch 语句和基于 Objective-C 及其相关类型转换的过时 API。应执行以下操作:

func matches(for regex: String, in text: String) -> [String] {
    var result = [String]()
    var startIndex = text.startIndex
    let endIndex = text.endIndex
    while let range = text.range(of: regex,
                                 options: .regularExpression,
                                 range: startIndex ..< endIndex)
    {
        result.append(String(text[range]))
        startIndex = range.upperBound
    }
    return result
}