在 space 之后删除

Question

我有这个数据集，我需要删除（删除并删除）名称城市之后的所有内容。我该怎么办？

dati1<- c("a - Novara Delete", "b - Torino Trash", "c - Milano", "f - Bari")
    
dati2 <-data.frame(do.call(rbind, strsplit(dati1, split = " - ")))

我试过：

c <- dati2$X2 %>%  mutate(dati2$X2 = sub("\s+[^ ]+$", "", dati2$X2))

Answer 1

您可以使用 separate:

tidyr::separate(data.frame(dati1), col = dati1, into = stringr::str_c("col", 1:2), extra = 'drop')

  col1   col2
1    a Novara
2    b Torino
3    c Milano
4    f   Bari

或以 R 为基数

data.frame(do.call(rbind, lapply(strsplit(dati1, split = "[^[:alnum:]]+"), head, 2)))

Answer 2

read.table 来自 base R

的选项

read.table(text = sub("^(\S+ - \S+)\s+.*", "\1", dati1),
     header = FALSE, sep = "-", strip.white = TRUE)
   V1     V2
1  a Novara
2  b Torino
3  c Milano
4  f   Bari

在 space 之后删除

Delete after the space

r

data-cleaning