如何访问 Mojolicious 模型中的会话数据
How to access session data in Mojolicious model
下面是一个示例 Mojolicious (6.14) 应用程序...对于 $_[0] 和其他不尽如人意的做法感到抱歉;我试着让它变得紧凑。
package ScopeTest;
use Mojo::Base 'Mojolicious';
sub startup {
my $app = shift;
$app->helper( hello => sub { "Hello!" } );
$app->helper( username => sub { $_[0]->session('username'); } );
$app->helper( model => sub { ScopeTest::Model->new( app => $_[0]->app ) } );
$app->helper( hasPerm => sub { $_[0]->model->hasPerm( @_ ) } );
$app->routes->get('/alice')->to('controller#alice');
$app->routes->get('/carol')->to('controller#carol');
$app->routes->get('/steve')->to('controller#steve');
}
##############################
package ScopeTest::Controller;
use Mojo::Base 'Mojolicious::Controller';
sub alice { $_[0]->session( username => "alice" ); $_[0]->render_message() }
sub carol { $_[0]->session( username => "carol" ); $_[0]->render_message() }
sub steve { $_[0]->session( username => "steve" ); $_[0]->render( text =>
sprintf "%s: %s\n", $_[0]->username, $_[0]->model->update_db ? 'Okay' : 'Fail' ) }
sub render_message { $_[0]->render( text =>
sprintf "%s: %s\n", $_[0]->username, $_[0]->hasPerm('canLogin') ? 'Okay' : 'Fail' ) }
##############################
package ScopeTest::Model;
use Mojo::Base -base;
has 'app';
my %perms = ( alice => [ qw{ canLogin } ],
carol => [ ],
steve => [ qw{ canUpdateDB } ] );
sub hasPerm {
my ( $self, $perm ) = @_;
no warnings 'uninitialized';
$self->app->log->debug("app->hello = " . $self->app->hello ); # OKAY
$self->app->log->debug("app->username = " . $self->app->username ); # FAILS
$self->app->log->debug("session('username') = " . $self->app->session('username') ); # FAILS
$self->app->log->debug("session->{'username'} = " . $self->app->session->{'username'} ); # FAILS
my $username; # = $self->app->username;
return grep { $_ eq $perm } @{ $perms{$username} };
}
sub update_db {
my ( $self, $data ) = @_;
$self->hasPerm('canUpdateDB') or return;
# else ...
return 1;
}
1;
虽然 $self->app->log->debug()
和 $self->app->dumper()
以及其他帮助者做正确的事,但 $self->app->session
却没有。
我知道传递 $app
被认为不太理想,但我希望以上内容至少可以工作...
除了一遍又一遍地传递用户名(这是一个玩具示例;真正的应用程序有几十种不同的方法,有时会相互调用,等等)是否有一种更简洁的方法来从型号 class?
PS — 在你说 Model->new(username => $self->session('username')
之前,这意味着知道 先验 ,我将需要哪些会话变量,以及在构造函数和属性列表中枚举它们;我希望如果我整个 $app
(甚至 $app->session
)都通过了,我可以让事情经得起未来的考验。
谢谢!
我犯的错误是:"session"信息与应用程序没有关联;它与控制器关联:
$app->helper( model => sub { ScopeTest::Model->new( ctrl => $_[0] ) } );
然后:
package ScopeTest::Model;
use Mojo::Base -base;
has 'ctrl';
...
$self->ctrl->app->log->debug("username = " . $self->ctrl->username );
是的,我知道将 Controller 传递给 Model 仍然不是最佳选择,但这至少解释了为什么我之前根本无法让它工作...
下面是一个示例 Mojolicious (6.14) 应用程序...对于 $_[0] 和其他不尽如人意的做法感到抱歉;我试着让它变得紧凑。
package ScopeTest;
use Mojo::Base 'Mojolicious';
sub startup {
my $app = shift;
$app->helper( hello => sub { "Hello!" } );
$app->helper( username => sub { $_[0]->session('username'); } );
$app->helper( model => sub { ScopeTest::Model->new( app => $_[0]->app ) } );
$app->helper( hasPerm => sub { $_[0]->model->hasPerm( @_ ) } );
$app->routes->get('/alice')->to('controller#alice');
$app->routes->get('/carol')->to('controller#carol');
$app->routes->get('/steve')->to('controller#steve');
}
##############################
package ScopeTest::Controller;
use Mojo::Base 'Mojolicious::Controller';
sub alice { $_[0]->session( username => "alice" ); $_[0]->render_message() }
sub carol { $_[0]->session( username => "carol" ); $_[0]->render_message() }
sub steve { $_[0]->session( username => "steve" ); $_[0]->render( text =>
sprintf "%s: %s\n", $_[0]->username, $_[0]->model->update_db ? 'Okay' : 'Fail' ) }
sub render_message { $_[0]->render( text =>
sprintf "%s: %s\n", $_[0]->username, $_[0]->hasPerm('canLogin') ? 'Okay' : 'Fail' ) }
##############################
package ScopeTest::Model;
use Mojo::Base -base;
has 'app';
my %perms = ( alice => [ qw{ canLogin } ],
carol => [ ],
steve => [ qw{ canUpdateDB } ] );
sub hasPerm {
my ( $self, $perm ) = @_;
no warnings 'uninitialized';
$self->app->log->debug("app->hello = " . $self->app->hello ); # OKAY
$self->app->log->debug("app->username = " . $self->app->username ); # FAILS
$self->app->log->debug("session('username') = " . $self->app->session('username') ); # FAILS
$self->app->log->debug("session->{'username'} = " . $self->app->session->{'username'} ); # FAILS
my $username; # = $self->app->username;
return grep { $_ eq $perm } @{ $perms{$username} };
}
sub update_db {
my ( $self, $data ) = @_;
$self->hasPerm('canUpdateDB') or return;
# else ...
return 1;
}
1;
虽然 $self->app->log->debug()
和 $self->app->dumper()
以及其他帮助者做正确的事,但 $self->app->session
却没有。
我知道传递 $app
被认为不太理想,但我希望以上内容至少可以工作...
除了一遍又一遍地传递用户名(这是一个玩具示例;真正的应用程序有几十种不同的方法,有时会相互调用,等等)是否有一种更简洁的方法来从型号 class?
PS — 在你说 Model->new(username => $self->session('username')
之前,这意味着知道 先验 ,我将需要哪些会话变量,以及在构造函数和属性列表中枚举它们;我希望如果我整个 $app
(甚至 $app->session
)都通过了,我可以让事情经得起未来的考验。
谢谢!
我犯的错误是:"session"信息与应用程序没有关联;它与控制器关联:
$app->helper( model => sub { ScopeTest::Model->new( ctrl => $_[0] ) } );
然后:
package ScopeTest::Model;
use Mojo::Base -base;
has 'ctrl';
...
$self->ctrl->app->log->debug("username = " . $self->ctrl->username );
是的,我知道将 Controller 传递给 Model 仍然不是最佳选择,但这至少解释了为什么我之前根本无法让它工作...