Pandas 在多个条件下删除行

Question

我有一个数据框：

from_dict = {'weekday': {1937: 'Thursday',
                    1938: 'Thursday',
                    1939: 'Thursday',
                    1940: 'Friday',
                    1941: 'Friday',
                    1942: 'Friday',
                    1943: 'Saturday'},
        'sort': {1937: 'pre',
                 1938: 'day',
                 1939: 'twi',
                 1940: 'pre',
                 1941: 'day',
                 1942: 'twi',
                 1943: 'pre'},
        'volume': {1937: 48840,
                   1938: 43936,
                   1939: 48393,
                   1940: 47675,
                   1941: 42271,
                   1942: 46270,
                   1943: 28721}}
df = pd.DataFrame.from_dict(from_dict)

       weekday sort  volume
1937  Thursday  pre   48840
1938  Thursday  day   43936
1939  Thursday  twi   48393
1940    Friday  pre   47675
1941    Friday  day   42271
1942    Friday  twi   46270
1943  Saturday  pre   28721

我只想切出 'weekday' == 'Friday' & 'sort' == 'day' 的行和 'weekday' == [= 的行28=] & 'sort' == 'day'

       weekday sort  volume
1937  Thursday  pre   48840
1939  Thursday  twi   48393
1940    Friday  pre   47675
1942    Friday  twi   46270
1943  Saturday  pre   28721

我更喜欢对行进行切片的原因是因为这个数据框被传递给 pivot_table 并且我不关心创建新变量或修改原始数据框。我尝试过按多个条件进行切片，但显然它没有用。

sort_df[((sort_df['weekday'] != 'Thursday') & (sort_df['sort'] != 'day'))]

这只会删除星期四和星期几的所有行。我知道答案会非常明显，我现在肯定知道了。

Answer 1

尝试：

>>> df[~(df["weekday"].isin(["Thursday", "Friday"])&df["sort"].eq("day"))]
       weekday sort  volume
1937  Thursday  pre   48840
1939  Thursday  twi   48393
1940    Friday  pre   47675
1942    Friday  twi   46270
1943  Saturday  pre   28721

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