sql 服务器,将字符串中的字符替换为 table 中的值
sql server, replace chars in string with values in table
如何用 table 中的值替换字符串中的值?
例如
select *
into #t
from
(
select 'bla'c1,'' c2 union all
select 'table'c1,'TABLE' c2 union all
select 'value'c1,'000' c2 union all
select '...'c1,'' c2
)t1
declare @s nvarchaR(max)='this my string and i want to replace all values that are in table #t'
我的 table 中有一些值,我想用字符串中的 C2 替换 C1。
结果应该是
this my string and i want to replace all 000 that are in TABLE #t
更新:
我用 CLR
解决了
using System;
using Microsoft.SqlServer.Server;
using System.Data.SqlTypes;
using System.Data.Linq;
namespace ReplaceValues
{
public partial class Functions
{
[SqlFunction
(
//DataAccess = DataAccessKind.Read,
SystemDataAccess = SystemDataAccessKind.Read
)
]
public static string ReplaceValues(string row, string delimitator, string values, string replace/*, bool CaseSensitive*/)
{
//return row;
string[] tmp_values = values.Split(new string[] { delimitator }, StringSplitOptions.None);
string[] tmp_replace = replace.Split(new string[] { delimitator }, StringSplitOptions.None);
row = row.ToUpper();
for (int i = 0; i < Math.Min(tmp_values.Length, tmp_replace.Length); i++)
{
row = row.Replace(tmp_values[i].ToUpper(), tmp_replace[i]);
}
return row;
}
}
}
然后
select *
into #t
from
(
select 'value1'OldValue,'one'NewValue union all
select 'value2'OldValue,'two'NewValue union all
select 'value3'OldValue,'three'NewValue union all
select 'value4'OldValue,'four'NewValue
)t1
select dbo.ReplaceValues(t1.column,'|',t2.v,t2.r)
from MyTable t1
cross apply
(
select dbo.inlineaggr(i1.OldValue,'|',1,1)v,
dbo.inlineaggr(i1.NewValue,'|',1,1)r
from #t i1
)t2
我必须改进它以更好地管理区分大小写,但性能还不错。
(另外 'inlineaggr' 是我几年前写的 CLR)
你可以通过递归来做到这一点。假设您有 table 个 find-replace 对,您可以对行进行编号,然后使用递归 cte:
create table #t(c1 nvarchar(100), c2 nvarchar(100));
insert into #t(c1, c2) values
('bla', ''),
('table', 'table'),
('value', '000'),
('...', '');
declare @s nvarchar(max) = 'this my string and i want to replace all values that are in table #t';
with ncte as (
select row_number() over (order by (select null)) as rn, *
from #t
), rcte as (
select rn, replace(@s, c1, c2) as newstr
from ncte
where rn = 1
union all
select ncte.rn, replace(rcte.newstr, ncte.c1, ncte.c2)
from ncte
join rcte on ncte.rn = rcte.rn + 1
)
select *
from rcte
where rn = 4
如何用 table 中的值替换字符串中的值?
例如
select *
into #t
from
(
select 'bla'c1,'' c2 union all
select 'table'c1,'TABLE' c2 union all
select 'value'c1,'000' c2 union all
select '...'c1,'' c2
)t1
declare @s nvarchaR(max)='this my string and i want to replace all values that are in table #t'
我的 table 中有一些值,我想用字符串中的 C2 替换 C1。
结果应该是
this my string and i want to replace all 000 that are in TABLE #t
更新: 我用 CLR
解决了using System;
using Microsoft.SqlServer.Server;
using System.Data.SqlTypes;
using System.Data.Linq;
namespace ReplaceValues
{
public partial class Functions
{
[SqlFunction
(
//DataAccess = DataAccessKind.Read,
SystemDataAccess = SystemDataAccessKind.Read
)
]
public static string ReplaceValues(string row, string delimitator, string values, string replace/*, bool CaseSensitive*/)
{
//return row;
string[] tmp_values = values.Split(new string[] { delimitator }, StringSplitOptions.None);
string[] tmp_replace = replace.Split(new string[] { delimitator }, StringSplitOptions.None);
row = row.ToUpper();
for (int i = 0; i < Math.Min(tmp_values.Length, tmp_replace.Length); i++)
{
row = row.Replace(tmp_values[i].ToUpper(), tmp_replace[i]);
}
return row;
}
}
}
然后
select *
into #t
from
(
select 'value1'OldValue,'one'NewValue union all
select 'value2'OldValue,'two'NewValue union all
select 'value3'OldValue,'three'NewValue union all
select 'value4'OldValue,'four'NewValue
)t1
select dbo.ReplaceValues(t1.column,'|',t2.v,t2.r)
from MyTable t1
cross apply
(
select dbo.inlineaggr(i1.OldValue,'|',1,1)v,
dbo.inlineaggr(i1.NewValue,'|',1,1)r
from #t i1
)t2
我必须改进它以更好地管理区分大小写,但性能还不错。 (另外 'inlineaggr' 是我几年前写的 CLR)
你可以通过递归来做到这一点。假设您有 table 个 find-replace 对,您可以对行进行编号,然后使用递归 cte:
create table #t(c1 nvarchar(100), c2 nvarchar(100));
insert into #t(c1, c2) values
('bla', ''),
('table', 'table'),
('value', '000'),
('...', '');
declare @s nvarchar(max) = 'this my string and i want to replace all values that are in table #t';
with ncte as (
select row_number() over (order by (select null)) as rn, *
from #t
), rcte as (
select rn, replace(@s, c1, c2) as newstr
from ncte
where rn = 1
union all
select ncte.rn, replace(rcte.newstr, ncte.c1, ncte.c2)
from ncte
join rcte on ncte.rn = rcte.rn + 1
)
select *
from rcte
where rn = 4