在 Oracle SQL 中使用 PERCENT_RANK

Question

谁能解释一下 Oracle SQL.

中 Percent_Rank() 背后的数学原理

SELECT ID, principal_disbursed, DUE_DATE, CREDIT_OFFICER, 
PERCENT_RANK() OVER (ORDER BY principal_disbursed)
FROM TABLE1

我需要了解后台的计算运行。

id	principal_disbursed	principal_repaid	due_date	repayment_date	credit_officer
1	4	4	12/10/2017	17/10/2017	John
2	4	4	10/11/2018	20/10/2018	Maria
3	7	7	18/08/2017	24/08/2017	Maria
4	0	0	04/08/2017	14/07/2017	Maria
5	0	0	04/08/2017	06/08/2017	John

Answer 1

下面是一个可能会给您提示的示例。我已经删除了日期。

with data(id,   principal_disbursed,    principal_repaid,   credit_officer) as (
select 1,   334,    334,'John' from dual union all
select 2,   184,    184,'Maria' from dual union all
select 3,   417,    417,'Maria' from dual union all
select 4,   500,    500,'Maria' from dual union all
select 5,   250,    250,'John' from dual
)
,cnt as (
select count(*)-1 cnt
from data
)
,one as (
SELECT ID, principal_disbursed, CREDIT_OFFICER
from data 
order by principal_disbursed
)
select one.*, case when rownum=1 then 0 else (rownum-1)/(select cnt from cnt) end
from one 
;

这与 :

相同

with data(id,   principal_disbursed,    principal_repaid,   credit_officer) as (
select 1,   334,    334,'John' from dual union all
select 2,   184,    184,'Maria' from dual union all
select 3,   417,    417,'Maria' from dual union all
select 4,   500,    500,'Maria' from dual union all
select 5,   250,    250,'John' from dual
)
SELECT ID, principal_disbursed, CREDIT_OFFICER, 
PERCENT_RANK() OVER (ORDER BY principal_disbursed)
FROM data

在 Oracle SQL 中使用 PERCENT_RANK

Using PERCENT_RANK in Oracle SQL

sql

oracle