我有两个 "exact" 函数，一个不起作用

Question

据我所知，我有两个功能完全相同。唯一的区别是一个是简洁的主体，另一个是 ES6 之前的长版。简洁的版本有效，而另一个则无效。加长版有什么问题？

//this version of the getActualSleepHours function works
const getActualSleepHours = () =>
  getSleepHours('monday') +
  getSleepHours('tuesday') +
  getSleepHours('wednesday') +
  getSleepHours('thursday') +
  getSleepHours('friday') +
  getSleepHours('saturday') +
  getSleepHours('sunday');

//this version of the getActualSleepHours function doesn't work
const getActualSleepHours = function() {
  getSleepHours('monday') +
    getSleepHours('tuesday') +
    getSleepHours('wednesday') +
    getSleepHours('thursday') +
    getSleepHours('friday') +
    getSleepHours('saturday') +
    getSleepHours('sunday');
}

Answer 1

() => something() 语法在 something() 之前插入一个隐含的 return。要使这些函数等价，请在函数中添加 return：

function() {
  return getSleepHours('monday') +
    getSleepHours('tuesday') +
    getSleepHours('wednesday') +
    getSleepHours('thursday') +
    getSleepHours('friday') +
    getSleepHours('saturday') +
    getSleepHours('sunday');
}

我有两个 "exact" 函数，一个不起作用

I have two "exact" functions and one doesn't work

javascript

function

syntax-error