如何在 Python 中将 OrderedDict 仅转换为值列表？

Question

我有一个 OrderedDict 对象，我想制作一个仅包含值的列表，同时保持它们在字典中的顺序相同。有开箱即用的方法吗？我的 OrderedDict 对象看起来像这样：

OrderedDict(
        [
            (
                datetime.datetime(2022, 5, 11, 7, 43, 0, 90913),
                {
                    "time": datetime.datetime(2022, 5, 11, 7, 43, 0, 90913),
                    "angle": 74.628235,
                    "sizes": [15.0, 65.0, 10.0, 130.0],
                },
            ),
            (
                datetime.datetime(2022, 5, 12, 6, 7, 8, 9),
                {
                    "time": datetime.datetime(2022, 3, 12, 6, 17, 8, 90980),
                    "angle": 8.054147,
                    "sizes": [15.0, 65.0, 10.0, 130.0],
                },
            )
        ]
    )

我的预期输出是这样的：

[[datetime.datetime(2022, 5, 11, 7, 43, 0, 90913),74.628235,[15.0, 65.0, 10.0, 130.0]],
[datetime.datetime(2022, 3, 12, 6, 17, 8, 90980),8.054147,[15.0, 65.0, 10.0, 130.0]]

Answer 1

仅供参考。

import datetime
OrderedDict = [
            (
                datetime.datetime(2022, 5, 11, 7, 43, 0, 90913),
                {
                    "time": datetime.datetime(2022, 5, 11, 7, 43, 0, 90913),
                    "angle": 74.628235,
                    "sizes": [15.0, 65.0, 10.0, 130.0],
                },
            ),
            (
                datetime.datetime(2022, 5, 12, 6, 7, 8, 9),
                {
                    "time": datetime.datetime(2022, 3, 12, 6, 17, 8, 90980),
                    "angle": 8.054147,
                    "sizes": [15.0, 65.0, 10.0, 130.0],
                },
            )
        ]
    

lst = [list(a[1].values()) for a in OrderedDict]
    

print(lst)

输出

[[datetime.datetime(2022, 5, 11, 7, 43, 0, 90913), 74.628235, [15.0, 65.0, 10.0, 130.0]],
[datetime.datetime(2022, 3, 12, 6, 17, 8, 90980), 8.054147, [15.0, 65.0, 10.0, 130.0]]]

用于字典。

import datetime
OrderedDict = [
            (
                datetime.datetime(2022, 5, 11, 7, 43, 0, 90913),
                {
                    "time": datetime.datetime(2022, 5, 11, 7, 43, 0, 90913),
                    "angle": 74.628235,
                    "sizes": [15.0, 65.0, 10.0, 130.0],
                },
            ),
            (
                datetime.datetime(2022, 5, 12, 6, 7, 8, 9),
                {
                    "time": datetime.datetime(2022, 3, 12, 6, 17, 8, 90980),
                    "angle": 8.054147,
                    "sizes": [15.0, 65.0, 10.0, 130.0],
                },
            )
        ]
    

lst = [a[1] for a in OrderedDict]
    

print(lst)

输出

[{'time': datetime.datetime(2022, 5, 11, 7, 43, 0, 90913), 'angle': 74.628235, 'sizes': [15.0, 65.0, 10.0, 130.0]},
 {'time': datetime.datetime(2022, 3, 12, 6, 17, 8, 90980), 'angle': 8.054147, 'sizes': [15.0, 65.0, 10.0, 130.0]}]

如何在 Python 中将 OrderedDict 仅转换为值列表？

How to convert OrderedDict to a list of values only, in Python?

python

ordereddictionary

仅供参考。

用于字典。