SQLAlchemy 检索不同的列

Question

这是我的代码：

import pandas as pd
from sqlalchemy import create_engine

db_username = "my_username"
db_pw = "my_password"
db_to_use = "my_database"
#####
engine = create_engine(
    "postgresql://" +
    db_username + ":" +
    db_pw +
    "@localhost:5432/" +
    db_to_use
    )
#####
connection = engine.connect()
fac_id_list = connection.execute (
    """
        select distinct
            a.name,
            replace(regexp_replace(regexp_replace(a.logo_url,'.*/logo','','i'),'production.*','','i'),'/','') as new_logo
        from
            sync_locations as a
        inner join
            public.vw_locations as b
            on
                a.name = b.location_name
        order by
             new_logo
        """
)

我想将 fac_id_list 的结果放入两个单独的列表中。一个列表将包含 a.name 和另一个 new_logo.

中的所有值

我该怎么做？

sql_results = []
for row in fac_id_list:
     sql_results.append(row)

这会将我的 SQL 查询中的每一列放入列表中，但我希望将它们分开。

Answer 1

当你遍历结果时，你可以将它们分散到单独的变量中并将它们附加到相应的列表中

names = []
logos = []
for name, logo in fac_id_list:
    names.append(name)
    logos.append(log)

SQLAlchemy 检索不同的列

SQLAlchemy Retrieving Different Columns

python

sqlalchemy

python-3.x