mysql 连接 2 个表的 COUNT 和 Sum

Question

我试了很多查询都没有正确的结果

我的目标是根据参加 branchid 的用户 ID 以及同一天在同一分支机构参加的用户数量获得用户佣金；

想要这样的结果

Date	totalAtt	Amount
2022-05-1	1	60 <-(50+20)-(5+5)
2022-05-2	2	50 <-(50+20)-(5+15)
2022-05-3	3	80 <-(80+30)-(25+5)
2022-05-4	1	200 <-(100+200)-(50+50) was on branchid =5

来自以下 2 个表格金钱

ID	Date	branchId	ca	ce	car	cer
1	2022-05-1	7	50	20	5	5
2	2022-05-1	5	100	20	10	5
3	2022-05-2	7	50	20	5	15
4	2022-05-2	5	70	20	10	5
5	2022-05-3	7	80	30	25	5
6	2022-05-3	5	90	20	35	5
7	2022-05-4	7	80	30	25	5
8	2022-05-4	5	100	200	50	50

att

ID	date	userid	branchId	att
1	2022-05-1	20	7	1
2	2022-05-2	20	7	1
3	2022-05-2	21	7	1
4	2022-05-3	20	7	1
5	2022-05-3	21	7	1
6	2022-05-3	22	7	1
7	2022-05-4	20	5	1

感谢进阶

Answer 1

您似乎想按日期计算 att，但要计算指定用户的金额。所以有条件地聚合

SELECT 
  a.date, 
  COUNT(DISTINCT a.USERID) AS totalatt ,
  SUM(CASE WHEN USERID = 20 THEN (m.ca+m.ce)-(m.car+m.cer) END) AS amount
FROM att a
LEFT JOIN money m   ON a.date = m.date   AND a.branchid = m.branchid
GROUP BY a.date HAVING AMOUNT > 0
ORDER BY a.date;

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