查询代码很多，如何在Oracle中减少代码长度SQL

Question

请教sql高手在这种情况下有什么用？

我需要调用一些查询 31 次，这是很多代码，是否可以使用一些好的选项来减少代码长度。

我在 table my_days + 其他栏中有 31 天栏

例如

with cte as

(

Select  day_1 as DAY_TOTAL, 1 as DAY, t1.column_1, t2.column_2, t3.column_3 from my_days my
left outer join table_1 t1 ....
left outer join table_2 t2 ....
left outer join table_3 t3 .... 
where user = :PARAMETER_USER and CODE =  :PARAMETER_CODE

union all

Select  day_2 as DAY_TOTAL, 2 as DAY, t1.column_1, t2.column_2, t3.column_3 from my_days my
left outer join table_1 t1 ....
left outer join table_2 t2 ....
left outer join table_3 t3 .... 
where user = :PARAMETER_USER and CODE =  :PARAMETER_CODE
---------

Select  day_31 as DAY_TOTAL, 3 as DAY, t1.column_1, t2.column_2, t3.column_3 from my_days my
left outer join table_1 t1 ....
left outer join table_2 t2 ....
left outer join table_3 t3 ....
where user = :PARAMETER_USER and CODE =  :PARAMETER_CODE
)

Select * from cte  + other join.....

也许在 union all 中创建函数并使用函数 insted 查询？

Answer 1

你可以UNPIVOT:

SELECT day_total, day, column1, column2, column3
FROM   (
         SELECT /*other_columns,*/ day_total, day
         FROM   my_days
         UNPIVOT (
           day_total FOR day IN (
             day_1 AS 1,
             day_2 AS 2,
             day_3 AS 3,
             day_4 AS 4,
             -- ...
             day_29 AS 29,
             day_30 AS 30,
             day_31 AS 31
           )
         )
       ) my
       left outer join table_1 t1 ....
       left outer join table_2 t2 ....
       left outer join table_3 t3 .... 
       + other join ...
WHERE  "USER" = :PARAMETER_USER
AND    CODE =  :PARAMETER_CODE

Answer 2

.. 或使用 MODEL 子句

WITH    my_days AS (Select 1 as day_1, 'xx' as col_x, 'yy' as col_y From DUAL),
        cte AS(SELECT INDX, day_x, col_x, col_y FROM my_days
               MODEL 
               DIMENSION BY(0 as INDX)
               MEASURES (0 as day_x, col_x, col_y)
               RULES ITERATE(31)
                      ( day_x[ITERATION_NUMBER+1] = ITERATION_NUMBER+1,
                        col_x[ANY] = col_x[0],
                        col_y[ANY] = col_y[0]
                      ) 
              )
SELECT * FROM ct
left outer join table_1 t1 
       ....

查询代码很多，如何在Oracle中减少代码长度SQL

A lot of code in query, how reduce code length in Oracle SQL

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