Cast Complex JSON 飞镖

Cast Complex JSON Dart

下面的 dart 代码允许您解码来自 resultValue 后端的 json,当我去创建具有以下值的列表我有以下错误,原因是什么?我该如何解决?

JSON Link

错误:

//Line:  return data.map((jsonObject) => new Manutenzione(

    flutter: Errore: type 'List<String>' 
is not a subtype of type 'String' in type cast

飞镖代码:

var urlmod = await Storage.leggi("URL") + "/services/rest/v3/processes/PreventiveMaint/instances";
    final resultValue = await apiRequest(Uri.parse(urlmod), {}, UrlRequest.GET, true);
    Map<String, dynamic> map = json.decode(resultValue);
    List<dynamic> data = map["data"];
    try {
      return data
          .map((jsonObject) => new Manutenzione(
                ["_id"] as String,
                ["_user"] as String,
                ["__user_description"] as String,
                ["Description"] as String,
                ["ShortDescr"] as String,
                ["_Site_description"] as String,
                ["_Team_description"] as String,
                ["_status_description"] as String,
                ["_Company_description"] as String,
              ))
          .toList();
    } catch (err) {
      print("Errore: " + err.toString());
    }
    return List.empty();
  }

JSON:

    {
       ...
        data: [
          {
            _id: value1,
            _user: value2,
            ..
          },
          {
            _id: value1,
            _user: value2,
            ..
          },

        ] 
    }

您忘记在方括号前指定 jsonObject

var urlmod = await Storage.leggi("URL") + "/services/rest/v3/processes/PreventiveMaint/instances";
    final resultValue = await apiRequest(Uri.parse(urlmod), {}, UrlRequest.GET, true);
    Map<String, dynamic> map = json.decode(resultValue);
    List<dynamic> data = map["data"];
    try {
      return data
          .map((jsonObject) => new Manutenzione(
                jsonObject["_id"] as String,
                jsonObject["_user"] as String,
                jsonObject["__user_description"] as String,
                jsonObject["Description"] as String,
                jsonObject["ShortDescr"] as String,
                jsonObject["_Site_description"] as String,
                jsonObject["_Team_description"] as String,
                jsonObject["_status_description"] as String,
                jsonObject["_Company_description"] as String,
              ))
          .toList();
    } catch (err) {
      print("Errore: " + err.toString());
    }
    return List.empty();
  }