行在列表中重复 python

Question

下一个问题我需要你的帮助，我需要 python 接收字符串“EEEEDDSGES”，输出将由重复的字符总和组成， E 4 2 1 1 1 S 1

下一个是我的代码，

diccionario = {}
contador = 0
for palabra in cadena:

    if palabra.upper() in diccionario:
        diccionario[palabra.upper()] += 1
    else:
        diccionario[palabra.upper()] = 1
for palabra in diccionario:
    frecuencia = diccionario[palabra]
    print(palabra, end=" ")
    print(frecuencia) ```

the output is ,

S,S,d,f,s
S 1
S 2
d 3
f 4
s 5

Answer 1

抱歉，我不明白这种语言是什么，但我想我明白你想做什么。为了理解，我更改了变量名称。

s="EEEEDDSGES"

letters={}

for i in s:
  i=i.upper()
  try:
    letters[i]+=1
  except(KeyError):
    letters.update({i:1})
    
for i in letters: print(f"{i}: {letters[i]}", end=" ")

Answer 2

尝试 itertools.groupby:

from itertools import groupby

s = "EEEEDDSGES"

for v, g in groupby(s):
    print(v, sum(1 for _ in g))

打印：

E 4
D 2
S 1
G 1
E 1
S 1

行在列表中重复 python

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