拆分列表中的单词并迭代字典

Question

我有一些代码，可以在文本中接收一串语言。

我的目标是将此输入转换为列表并在字典中遍历此列表以用作值输出的键。我将此输出发送到列表以供稍后使用。

我期望的输出是 [57, 20, 22, 52, 60... etc] 但目前，我收到

[57, None, None, None, None, None, None...等等]

我的第一个输出是正确的，但之后，它似乎没有在字典中找到正确的值。

下面的代码。


l_languages = []

language_dict = { 'Afrikaans' : 57, 'Arabic' : 20, 'Assistive communication' : 21, 'AUSLAN' : 22, 'Bosnian' : 52,'Burmese' : 60, 'Cantonese' : 23, 'Croation' : 54, 'Dutch' : 50,'French' : 24, 'German' : 25, 'Greek' : 26,'Hindi' : 27, 'Indigenous Australian' : 310, 'Indonesian' : 56, 'Italian' : 28, 'Japanese' : 62, 'Korean' : 48, 'Mandarin' : 29, 'Nepali' : 55, 'Polish' : 30}

data = "Afrikaans, Arabic, Assistive communication, AUSLAN, Bosnian, Burmese, Cantonese, Croation, Dutch"


language_list = data.split(',')

for language in language_list:
    id = language_dict.get(language)
    l_languages.append(id)
    
print(l_languages)

current output = [57, None, None, None, None, None, None....etc]

Answer 1

您忽略了语言列表中的白色 space。您应该删除前导和尾随的白色 space 并访问您的字典。

如果您只是在“,”处拆分列表，那么在后面的每种语言前面都会有一个前导白色 space。只是不是第一个，这解释了你当前的输出

Answer 2

看看你的language_list。它有前导空格。您需要在每个元素上调用 strip() 并获得预期结果

l_languages = []

language_dict = { 'Afrikaans' : 57, 'Arabic' : 20, 'Assistive communication' : 21, 'AUSLAN' : 22, 'Bosnian' : 52,'Burmese' : 60, 'Cantonese' : 23, 'Croation' : 54, 'Dutch' : 50,'French' : 24, 'German' : 25, 'Greek' : 26,'Hindi' : 27, 'Indigenous Australian' : 310, 'Indonesian' : 56, 'Italian' : 28, 'Japanese' : 62, 'Korean' : 48, 'Mandarin' : 29, 'Nepali' : 55, 'Polish' : 30}

data = "Afrikaans, Arabic, Assistive communication, AUSLAN, Bosnian, Burmese, Cantonese, Croation, Dutch"

language_list = data.split(',')
print(language_list)
for language in language_list:
    val = language_dict.get(language.strip())
    l_languages.append(val)
    
print(l_languages)

['Afrikaans', ' Arabic', ' Assistive communication', ' AUSLAN', ' Bosnian', ' Burmese', ' Cantonese', ' Croation', ' Dutch'] # list with leading spaces
[57, 20, 21, 22, 52, 60, 23, 54, 50] # right result

Answer 3

l_languages = []
language_dict = { 'Afrikaans' : 57, 'Arabic' : 20, 'Assistive communication' : 21, 'AUSLAN' : 22, 'Bosnian' : 52,'Burmese' : 60, 'Cantonese' : 23, 'Croation' : 54, 'Dutch' : 50,'French' : 24, 'German' : 25, 'Greek' : 26,'Hindi' : 27, 'Indigenous Australian' : 310, 'Indonesian' : 56, 'Italian' : 28, 'Japanese' : 62, 'Korean' : 48, 'Mandarin' : 29, 'Nepali' : 55, 'Polish' : 30}
data = "Afrikaans, Arabic, Assistive communication, AUSLAN, Bosnian, Burmese, Cantonese, Croation, Dutch"
language_list=[x.strip() for x in data.split(',')]
for language in language_list:
    id = language_dict.get(language)
    l_languages.append(id)
#output
[57, 20, 21, 22, 52, 60, 23, 54, 50]

Answer 4

最简单的方法

#Devil
language_dict = { 'Afrikaans' : 57, 'Arabic' : 20, 'Assistive communication' : 21,
                 'AUSLAN' : 22, 'Bosnian' : 52,'Burmese' : 60, 'Cantonese' : 23,
                 'Croation' : 54, 'Dutch' : 50,'French' : 24, 'German' : 25, 'Greek' : 26,
                 'Hindi' : 27, 'Indigenous Australian' : 310, 'Indonesian' : 56, 'Italian' : 28,
                 'Japanese' : 62, 'Korean' : 48, 'Mandarin' : 29, 'Nepali' : 55, 'Polish' : 30}
data = "Afrikaans, Arabic, Assistive communication, AUSLAN, Bosnian, Burmese, Cantonese, Croation, Dutch"

data_list = data.split(",") #split the data
data_list = [d.strip() for d in data_list] #remove white space
l_languages = [language_dict[z] for z in data_list] #find the value using key
print(data_list)
print(l_languages)

拆分列表中的单词并迭代字典

Split word in list and iterate dictionary

python

dictionary

list