如何 Select 忽略关系的多列上的不同行?
How do I Select distinct rows on multiple columns ignoring relations?
假设我们有这样一个 table:
ID1 ID2 ID3 ID3
----------- ----------- ----------- -----------
101 44 40 46
108 44 37 46
108 44 40 46
101 44 30 36
101 44 30 46
181 44 40 46
397 44 40 46
138 44 40 46
108 44 37 43
108 44 30 46
期望的输出是一个 select 查询,给出了这个:
ID1 ID2 ID3 ID4
----------- ----------- ----------- -----------
101 44 30 36
108 NULL 37 43
111 NULL 40 46
138 NULL NULL NULL
181 NULL NULL NULL
397 NULL NULL NULL
我有这个 select 查询几乎可以满足我的要求:
USE databaseName
DECLARE @start DATE
DECLARE @stop DATE
set @start = '2021-01-01'
set @stop = '2021-12-31'
SELECT DISTINCT t.ID1, NULL ID2, NULL ID3, NULL ID4
FROM ..IdTable t WHERE CreateDate BETWEEN @start AND @stop
UNION
SELECT DISTINCT NULL ID1, t.ID2, NULL ID3, NULL ID4
FROM ..IdTable t WHERE CreateDate BETWEEN @start AND @stop
UNION
SELECT DISTINCT NULL ID1, NULL ID2, t.ID3, NULL ID4
FROM ..IdTable t WHERE CreateDate BETWEEN @start AND @stop
UNION
SELECT DISTINCT NULL ID1, NULL ID2, NULL ID3, t.ID4
FROM ..IdTable t WHERE CreateDate BETWEEN @start AND @stop
输出:
ID1 ID2 ID3 ID4
----------- ----------- ----------- -----------
NULL NULL NULL 36
NULL NULL NULL 43
NULL NULL NULL 46
NULL NULL 30 NULL
NULL NULL 37 NULL
NULL NULL 40 NULL
NULL 44 NULL NULL
101 NULL NULL NULL
108 NULL NULL NULL
111 NULL NULL NULL
138 NULL NULL NULL
181 NULL NULL NULL
397 NULL NULL NULL
- 可以优化我的 select 查询吗?
- 能否创建一个查询来提供我想要的输出?
也许可以使用 dense_rank()
select ID1,ID2,ID3,ID4
from
(
Select distinct ID1, r= dense_rank() over (order by ID1 asc) from IdTable
)T1
full join
(
Select distinct ID2, r=dense_rank() over (order by ID2 asc) from IdTable
)T2 on T1.R=T2.R
full join
(
Select distinct ID3, r=dense_rank() over (order by ID3 asc) from IdTable
)T3 on T1.R=T3.R
full join
(
Select distinct ID4, r=dense_rank() over (order by ID4 asc) from IdTable
)T4 on T1.R=T4.R
假设我们有这样一个 table:
ID1 ID2 ID3 ID3
----------- ----------- ----------- -----------
101 44 40 46
108 44 37 46
108 44 40 46
101 44 30 36
101 44 30 46
181 44 40 46
397 44 40 46
138 44 40 46
108 44 37 43
108 44 30 46
期望的输出是一个 select 查询,给出了这个:
ID1 ID2 ID3 ID4
----------- ----------- ----------- -----------
101 44 30 36
108 NULL 37 43
111 NULL 40 46
138 NULL NULL NULL
181 NULL NULL NULL
397 NULL NULL NULL
我有这个 select 查询几乎可以满足我的要求:
USE databaseName
DECLARE @start DATE
DECLARE @stop DATE
set @start = '2021-01-01'
set @stop = '2021-12-31'
SELECT DISTINCT t.ID1, NULL ID2, NULL ID3, NULL ID4
FROM ..IdTable t WHERE CreateDate BETWEEN @start AND @stop
UNION
SELECT DISTINCT NULL ID1, t.ID2, NULL ID3, NULL ID4
FROM ..IdTable t WHERE CreateDate BETWEEN @start AND @stop
UNION
SELECT DISTINCT NULL ID1, NULL ID2, t.ID3, NULL ID4
FROM ..IdTable t WHERE CreateDate BETWEEN @start AND @stop
UNION
SELECT DISTINCT NULL ID1, NULL ID2, NULL ID3, t.ID4
FROM ..IdTable t WHERE CreateDate BETWEEN @start AND @stop
输出:
ID1 ID2 ID3 ID4
----------- ----------- ----------- -----------
NULL NULL NULL 36
NULL NULL NULL 43
NULL NULL NULL 46
NULL NULL 30 NULL
NULL NULL 37 NULL
NULL NULL 40 NULL
NULL 44 NULL NULL
101 NULL NULL NULL
108 NULL NULL NULL
111 NULL NULL NULL
138 NULL NULL NULL
181 NULL NULL NULL
397 NULL NULL NULL
- 可以优化我的 select 查询吗?
- 能否创建一个查询来提供我想要的输出?
也许可以使用 dense_rank()
select ID1,ID2,ID3,ID4
from
(
Select distinct ID1, r= dense_rank() over (order by ID1 asc) from IdTable
)T1
full join
(
Select distinct ID2, r=dense_rank() over (order by ID2 asc) from IdTable
)T2 on T1.R=T2.R
full join
(
Select distinct ID3, r=dense_rank() over (order by ID3 asc) from IdTable
)T3 on T1.R=T3.R
full join
(
Select distinct ID4, r=dense_rank() over (order by ID4 asc) from IdTable
)T4 on T1.R=T4.R