如何根据组列对序列进行分组分配groupid

Question

下面是我的数据框

ColA  ColB  Time          ColC
A     B     01-01-2022    ABC
A     B     02-01-2022    ABC
A     B     07-01-2022    XYZ
A     B     11-01-2022    IJK
A     B     14-01-2022    ABC

想要的结果：

ColA  ColB  Time          ColC   groupID
A     B     01-01-2022    ABC     1
A     B     02-01-2022    ABC     1
A     B     07-01-2022    XYZ     2
A     B     11-01-2022    IJK     3 
A     B     14-01-2022    ABC     4

更新：下面是在 cumsum

之后执行的代码

df['ColC'] = df['ColC'].ne(df['ColC'].shift(1)).groupby([df['ColA'],
                                                                                                                        df['ColB']]).cumsum()


ColA  ColB  Time          ColC   groupID
A     B     01-01-2022    ABC     1
A     B     02-01-2022    ABC     1
A     B     07-01-2022    XYZ     2
A     B     11-01-2022    XYZ     3 
A     B     14-01-2022    XYZ     4
A     B     14-01-2022    XYZ     4

提前致谢

Answer 1

逻辑并不完全清楚，但看起来您正在尝试按周数（和 ColC）分组：

df['groupID'] = (df
 .groupby([pd.to_datetime(df['Time'], dayfirst=True).dt.isocalendar().week,
           'ColC'], sort=False)
 .ngroup().add(1)
)

输出：

  ColA ColB        Time ColC  groupID
0    A    B  01-01-2022  ABC        1
1    A    B  02-01-2022  ABC        1
2    A    B  07-01-2022  XYZ        2
3    A    B  11-01-2022  IJK        3
4    A    B  14-01-2022  ABC        4

如何根据组列对序列进行分组分配groupid

How to group sequence based on group column assign a groupid

python

merge

datetime

join

pandas