根据多列条件删除行

Question

鉴于tablehave，我想根据to_deletetable.

删除满足条件的记录

data have;
infile datalines delimiter="|";
input id :8. item :. datetime : datetime18.;
format datetime datetime18.;
datalines;
111|Basket|30SEP20:00:00:00
111|Basket|30SEP21:00:00:00
111|Basket|31DEC20:00:00:00
111|Backpack|31MAY22:00:00:00
222|Basket|31DEC20:00:00:00
222|Basket|30JUN20:00:00:00
;

+-----+----------+------------------+
| id  |   item   |     datetime     |
+-----+----------+------------------+
| 111 | Basket   | 30SEP20:00:00:00 |
| 111 | Basket   | 30SEP21:00:00:00 |
| 111 | Basket   | 31DEC20:00:00:00 |
| 111 | Backpack | 31MAY22:00:00:00 |
| 222 | Basket   | 31DEC20:00:00:00 |
| 222 | Basket   | 30JUN20:00:00:00 |
+-----+----------+------------------+

data to_delete;
infile datalines delimiter="|";
input id :8. item :. datetime : datetime18.;
format datetime datetime18.;
datalines;
111|Basket|30SEP20:00:00:00
111|Backpack|31MAY22:00:00:00
222|Basket|30JUN20:00:00:00
;

+-----+----------+------------------+
| id  |   item   |     datetime     |
+-----+----------+------------------+
| 111 | Basket   | 30SEP20:00:00:00 |
| 111 | Backpack | 31MAY22:00:00:00 |
| 222 | Basket   | 30JUN20:00:00:00 |
+-----+----------+------------------+

以前我都是用catx()函数来操作，在where语句中拼接条件，不知道有没有更好的方法

proc sql;
    delete from have
        where catx('|',id,item,datetime) in 
              (select catx('|',id,item,datetime) from to_delete);
run;

+-----+--------+------------------+
| id  |  item  |     datetime     |
+-----+--------+------------------+
| 111 | Basket | 30SEP21:00:00:00 |
| 111 | Basket | 31DEC20:00:00:00 |
| 222 | Basket | 31DEC20:00:00:00 |
+-----+--------+------------------+

请注意，它应该允许 have table 比 table to_delete 有更多的列。

Answer 1

您可以使用 except from 来计算两个集合的差异集：

proc sql;
  create table want as 
  select * from have except select * from to_delete
  ;
quit;

根据多列条件删除行

Deleting rows based on multiple columns conditions

sas

proc-sql