SQL

Question

我正在尝试在我的数据库中插入一个新的位置记录...然后在稍后的 select 语句的 where 子句中重用新创建的 id 的值。但是我遇到语法错误。

代码：

USE Widgets;
GO
DECLARE     @userPrincipalName VARCHAR(100),
            @displayName VARCHAR(100),
            @domainName VARCHAR(100),
            @locationId INT,
            @uname VARCHAR(100);
DECLARE     @newLocationId TABLE (
            id INT
            );

-- CREATE NEW LOCATION, FLAG AS PRIMARY

IF NOT EXISTS (SELECT *
                FROM Locations
                WHERE LocationName = 'outer-space')
    BEGIN
        INSERT INTO Locations
        OUTPUT Inserted.ID INTO @newLocationId
        SELECT 'out-space' ,'the final frontier', 60, 1
    END

-- MUCH LATER IN THE SQL CODE:

IF NOT EXISTS (SELECT *
                FROM LocationEnvironment
                WHERE LocationId = @newLocationId.id
                )
    BEGIN
        INSERT INTO LocationEnvironment
        SELECT 1, id
        FROM @newLocationId
    END

错误是“必须声明标量变量”，它死于 SELECT 语句中的 WHERE 子句。

我也试过这样的：

IF NOT EXISTS (SELECT *
                FROM LocationEnvironment
                WHERE LocationId = id
                FROM @newLocationId
                )

但这也不管用。如有任何提示，我们将不胜感激。

Answer 1

在 -- MUCH LATER IN THE SQL CODE:

之前添加 GO 语句

这会将上述语句发送到服务器。

Answer 2

我认为您需要将 SQL 代码部分中的 WHERE 子句从临时 table:

更新为 select

WHERE LocationId = @newLocationId.id

应该是：

WHERE LocationId = (select top 1 id from @newLocationId)

或者如果您的 table 变量中可能有多个值：

WHERE LocationId in (select id from @newLocationId)

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