如何在不使用字典的情况下输出所有 .csv 值？

Question

我在将所有 .csv 值输出到我的 .json 文件时遇到问题。该脚本仅输出 .csv 行中的最后一个值。我需要输出所有值并用 space 分隔，而不使用 .csv 值的字典。这是我的代码。

    #getting variables from csv file
with open(csvfilepath, 'r', encoding='utf-8') as csvfile:
    csvreader = csv.reader(csvfile)
    next(csvreader)
    for row in csvreader:
        args_str = row[5][1:] 

#select json template
jsonfilename = input("Enter .json template name: ")
jsonfilepath = jsontempdir + jsonfilename 
#loading json file
with open(jsonfilepath,'r+', encoding='utf-8') as jsonfile:
    data = json.load(jsonfile)
# put args_str in "Args" key
data["Config"]["Script"].update({"Args": args_str})

这里是例子.csv

['#STEP', 'dog', '&NONE', '*0', '^NOP', 'foo', '~1000', '!NONE', '!NONE']
['#STEP', 'cat', '&NONE', '*0', '^NOP', 'bar', '~1000', '!NONE', '!NONE']
['#STEP', '', '&NONE', '*0', '^NOP', 'baz', '~1000', '!NONE', '!NONE']

这是我当前的 .json 输出

    "Config": {
        "CustomID": "UPDATED AFTER IMPORT",
        "Name": "Execute script function.py",
        "Script": {
            "Args": "baz",
            "ChangeID": "",
            "Exists": true,
            "Lang": "",
            "Name": "",
            "Text": ""

这是我想要的输出

    "Config": {
        "CustomID": "UPDATED AFTER IMPORT",
        "Name": "Execute script function.py",
        "Script": {
            "Args": "foo bar baz",
            "ChangeID": "",
            "Exists": true,
            "Lang": "",
            "Name": "",
            "Text": ""

Answer 1

您当前在循环的每次迭代中覆盖 args_str 中的值。相反，您可以尝试像这样连接第 5 列中的所有值：

with open(csvfilepath, 'r', encoding='utf-8') as csvfile:
    csvreader = csv.reader(csvfile)
    next(csvreader)
    args_str = " ".join(row[5] for row in csvreader)

如何在不使用字典的情况下输出所有 .csv 值？

How to output all .csv values without using a dictionary?

python

csv

json