snowflake sql - 横向展平函数与 sql 服务器比较 - Split_String()

Question

我的任务是比较计数，看看它是否 > 0

下方sql雪花

select 'abc'
from tableA
where 
(SELECT count(T1.value) as val
from tableA,
    lateral flatten(input=>split(abc, ',')) T1
    INNER JOIN (select count(T2.value) as val from 
lateral flatten(input=>split('1,2', ','))) as T2 on T1.val = T2.val) > 0

这是错误消息

SQL compilation error: error line 7 at position 29 invalid identifier 'T2.VALUE'

Sql 有效的服务器比较。

(select Count(T1.value) as [Count] from STRING_SPLIT(abc,',') AS T1
    INNER JOIN STRING_SPLIT('9,10', ',') AS T2 on T1.value = T2.value))>0

Answer 1

您可能需要像这样重新定位 -

select 'abc'
from tableA
where
(select count(*) from
(SELECT count(flat_tab_alias1.value) as val
from tableA,
lateral flatten(input=>split(abc, ',')) flat_tab_alias1
) as T1
INNER JOIN
(
select count(flat_tab_alias2.value) as val from
lateral flatten(input=>split('1,2', ',')) flat_tab_alias2
) as T2
on T1.val = T2.val) > 0;

'ABC'

0 Row(s) produced.

来源如下 table -

select * from tablea;

ABC
a,b,c,d,e,f,g

Answer 2

你 SQL 有很多问题，但鉴于我们正在努力 T-SQL 让我们解码它。

(select Count(T1.value) as [Count] from STRING_SPLIT(abc,',') AS T1
    INNER JOIN STRING_SPLIT('9,10', ',') AS T2 on T1.value = T2.value))>0

这段代码正在拆分一个字符串数组，并将其连接到一组“已知”值，计算均值如何相等，并询问是否存在任何重叠。

ARRAY_OVERLAP 回答这个问题，并使用 SPLIT 制作数组：

SELECT abc, 
    split(abc, ',') as a1,
    split('1,2', ',') as a2,
    ARRAYS_OVERLAP( a1, a2)
FROM values
    ('1'),
    ('0,4'),
    ('0,1,5')
    t(abc);

给出：

ABC	A1	A2	ARRAYS_OVERLAP( A1, A2)
1	[ "1" ]	[ "1", "2" ]	TRUE
0,4	[ "0", "4" ]	[ "1", "2" ]	FALSE
0,1,5	[ "0", "1", "5" ]	[ "1", "2" ]	TRUE

所以你的 SQL 应该是：

SELECT 'abc', abc
FROM tableA
WHERE ARRAYS_OVERLAP( split(abc,','), split('1,2',','));

其中包含虚拟数据：

    select * from values
    ('1'),
    ('0,4'),
    ('0,1,5')

给出：

'ABC'	ABC
abc	1
abc	0,1,5

snowflake sql - 横向展平函数与 sql 服务器比较 - Split_String()

snowflake sql - lateral flatten function compare with sql server - Split_String()

sql-server-2008-r2

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