Rails 6 个来自 Sidekiq Job 的抓取结果 - 这可能吗？

Question

我有 Sidekiq 工作 (SyncProductsWorker)，它会触发一个 class Imports::SynchronizeProducts 负责几个外部 API 调用。

module Imports
  class SyncProductsWorker
    include Sidekiq::Worker
    sidekiq_options queue: 'imports_sync'

    def perform(list)
      ::Imports::SynchronizeProducts.new(list).call
    end
  end
end

Imports::SynchronizeProducts class 给出了一组带有一些注释的 monad 结果，例如

=> [Failure("999999 Product code is not valid"), Failure(" 8888889 Product code is not valid")]

我想捕获这些结果以在 FE 上显示它们。有可能这样做吗？如果我这样做：

def perform(list)
  response = ::Imports::SynchronizeProducts.new(list).call
  response
end

然后在控制器内部：

def create
  response = ::Imports::SyncProductsWorker.perform_async(params[:product_codes])

  render json: { result: response, head: :ok }
end

结果我会有一些数字

=> "df3615e8efc56f8a062ba1c2"

Answer 1

我不相信你想要的是可能的。

https://github.com/mperham/sidekiq/issues/3532

The return value will be GC'd like any other unused data in a Ruby process. Jobs do not have a "result" in Sidekiq and Sidekiq does nothing with the value.

您可能需要某种模型来跟踪您的后台任务。这是即兴的，但应该给你一个想法。

EG

# @attr result [Array]
# @attr status [String] Values of 'Pending', 'Error', 'Complete', etc..
class BackgroundTask < ActiveRecord
  attr_accessor :product_codes
  after_create :enqueue
  
  def enqueue
    ::Imports::SyncProductsWorker.perform_async(product_codes, self.id)
  end
end

def perform(list, id)
  response = ::Imports::SynchronizeProducts.new(list).call
  if (response.has_errors?)
    BackgroundTask.find(id).update(status: 'Error', result: response)
  else
    BackgroundTask.find(id).update(status: 'Complete', result: response)
  end
end

然后只需将 BackgroundTask 模型用于前端显示即可。

Rails 6 个来自 Sidekiq Job 的抓取结果 - 这可能吗？

Rails 6 grab results from Sidekiq Job - is it possible?

ruby-on-rails

ruby

sidekiq