SQL 分组在一起，这样数据就不会重复

Question

在 table 中有数据，并尝试查询它，以便数据读取例如像 Motrin |毫克 | 25 | 4 |天|疼痛，排成一列。从图像中...我将它们全部放在“答案”栏下。我的查询已将它们全部显示出来……但它重复了数据。任何人都可以帮助将其分组到 DrilldownQuestionID 下吗？

下面是我创建的示例数据：

PracticeID	PatientID	ParentPageID	ParentPageNumber	QuestionID	DrilldownQuestionID	DrilldownAnsRecordID	EncounterID	Answer
1	111111	48	5	1475	2091	1	encounter1	Tylenol
1	111111	48	5	1475	2092	1	encounter1	mg
1	111111	48	5	1475	2093	1	encounter1	500
1	111111	48	5	1475	2094	1	encounter1	3
1	111111	48	5	1475	2095	1	encounter1	day
1	111111	48	5	1475	2096	1	encounter1	Headache
1	111111	48	5	1475	2091	2	encounter1	Motrin
1	111111	48	5	1475	2092	2	encounter1	mg
1	111111	48	5	1475	2093	2	encounter1	25
1	111111	48	5	1475	2094	2	encounter1	4
1	111111	48	5	1475	2095	2	encounter1	day
1	111111	48	5	1475	2096	2	encounter1	Pain

下面是我的查询；

    select distinct j.Answer as Name, 
    n.Answer as Dosage,
    k.Answer as [Dosage Unit], 
    o.Answer as [How Many],
    l.Answer as [How Often], 
    m.Answer as [Taken For]
from
    (select isnull(a.[Answer],'') as Answer, 
        a.EncounterID  
    from C_ItemDrillDown c join D_AWVAnswers a 
        on c.ItemDrilldownID = a.DrilldownQuestionID 
        and a.QuestionID = 1475 
        and a.DrilldownQuestionID = 2091
    where a.EncounterID = @EncounterID) as j
        join
    (select isnull(a.[Answer],'') as Answer, 
        a.EncounterID  
    from C_ItemDrillDown c join D_AWVAnswers a 
        on c.ItemDrilldownID = a.DrilldownQuestionID 
        and a.QuestionID = 1475 
        and a.DrilldownQuestionID = 2093
    where a.EncounterID = @EncounterID) as n
        on j.EncounterID = n.EncounterID
        join
    (select isnull(a.[Answer],'') as Answer, 
        a.EncounterID 
    from C_ItemDrillDown c join D_AWVAnswers a 
        on c.ItemDrilldownID = a.DrilldownQuestionID 
        and a.QuestionID = 1475 
        and a.DrilldownQuestionID = 2092
    where a.EncounterID = @EncounterID) as k
        on n.encounterID = k.EncounterID
        join
    (select isnull(a.[Answer],'') as Answer, 
        a.EncounterID  
    from C_ItemDrillDown c join D_AWVAnswers a 
        on c.ItemDrilldownID = a.DrilldownQuestionID 
        and a.QuestionID = 1475 
        and a.DrilldownQuestionID = 2094
    where a.EncounterID = @EncounterID) as o
        on k.EncounterID = o.EncounterID
        join
    (select isnull(a.[Answer],'') as Answer, 
        a.EncounterID 
    from C_ItemDrillDown c join D_AWVAnswers a 
        on c.ItemDrilldownID = a.DrilldownQuestionID 
        and a.QuestionID = 1475 
        and a.DrilldownQuestionID = 2095
    where a.EncounterID = @EncounterID) as l
        on o.encounterID = l.EncounterID
        join
    (select isnull(a.[Answer],'') as Answer, 
        a.EncounterID 
    from C_ItemDrillDown c join D_AWVAnswers a 
        on c.ItemDrilldownID = a.DrilldownQuestionID 
        and a.QuestionID = 1475 
        and a.DrilldownQuestionID = 2096
    where a.EncounterID = @EncounterID) as m
        on l.encounterID = m.EncounterID

我想要的结果是：

Name	Dosage	Dosage Unit	How Many	How Often	Taken For
Tylenol	500	mg	3	day	Headache
Motrin	25	mg	4	day	Pain

Answer 1

所以看起来你在 straight-forward 枢轴之后，类似于以下内容：

select 
  max(case when DrilldownQuestionID = 2091 then Answer end) [Name],
  max(case when DrilldownQuestionID = 2092 then Answer end) [Dosage Unit],
  max(case when DrilldownQuestionID = 2093 then Answer end) Dosage,
  max(case when DrilldownQuestionID = 2094 then Answer end) [How Many],
  max(case when DrilldownQuestionID = 2095 then Answer end) [How Often],
  max(case when DrilldownQuestionID = 2096 then Answer end) [Taken For]
from t
group by DrilldownAnsRecordID;

我已经省略了多余的（针对问题的）列，如果您需要使用它们，您也会group-by。

结果：

见Demo Fiddle

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