Python:如何输入两个元素作为输入,但在列表中将其保存为一个
Python: how to enter two elements as an input but save it as one in the list
我正在学习 Python 我正在尝试通过输入分别输入工人的姓名和姓氏,然后将其作为一个“元素”或“对象”保存在列表中(不确定怎么称呼。
所以它会是这样的:
name1 = input("Enter the name: John ")
lastname1 = input("Enter the last name: Conor ")
name2 = input("Enter the name: Michael ")
lastname2 = input("Enter the last name: Scott ")
结果:列表 = [John Conor, Michael Scott]
这就是我目前所得到的,我尽可能多地进行了谷歌搜索,但我就是找不到任何我需要的示例:
class Worker:
def __init__(self, name, lastname):
self.name = name
self.lastname = lastname
def name_lastname(self):
print(self.name, self.name)
class Project:
def __init__(self, name, worker):
self.name = name
self.worker = worker
list = []
name1 = input("Enter the name: ")
lastname1 = input("Enter the last name: ")
name2 = input("Enter the name: ")
lastname2 = input("Enter the last name: ")
请不要使用列表作为变量名。列表是 python 中的 built-in 类型。
对于你的例子,你可以试试这个:
li = []
name1 = input("Enter the name: ")
lastname1 = input("Enter the last name: ")
li.append(name1 + ' ' + lastname1)
name2 = input("Enter the name: ")
lastname2 = input("Enter the last name: ")
li.append(name2 + ' ' + lastname2)
print(li)
# [John Conor, Michael Scott]
我想你要找的是这样的:
class Worker:
def __init__(self, name, lastname):
self.name = name
self.lastname = lastname
def __repr__(self):
return f'{self.name} {self.lastname}'
list_ = [] # note variable name
name1 = input("Enter the name: ")
lastname1 = input("Enter the last name: ")
list_.append(Worker(name1, lastname1))
name2 = input("Enter the name: ")
lastname2 = input("Enter the last name: ")
list_.append(Worker(name2, lastname2))
for worker in list_:
print(worker)
使用 lambda 函数执行此操作的最佳方法
#Devil
name1 = input("Enter the name: John ")
lastname1 = input("Enter the last name: Conor ")
name2 = input("Enter the name: Michael ")
lastname2 = input("Enter the last name: Scott ")
list_name = []
joint_name = lambda x, y : x + ' ' + y
list_name.append(joint_name(name1, lastname1))
list_name.append(joint_name(name2, lastname2))
#desire list
print("output :" , list_name)
#output : ['John Conor', 'Michael Scott']
我正在学习 Python 我正在尝试通过输入分别输入工人的姓名和姓氏,然后将其作为一个“元素”或“对象”保存在列表中(不确定怎么称呼。
所以它会是这样的:
name1 = input("Enter the name: John ")
lastname1 = input("Enter the last name: Conor ")
name2 = input("Enter the name: Michael ")
lastname2 = input("Enter the last name: Scott ")
结果:列表 = [John Conor, Michael Scott]
这就是我目前所得到的,我尽可能多地进行了谷歌搜索,但我就是找不到任何我需要的示例:
class Worker:
def __init__(self, name, lastname):
self.name = name
self.lastname = lastname
def name_lastname(self):
print(self.name, self.name)
class Project:
def __init__(self, name, worker):
self.name = name
self.worker = worker
list = []
name1 = input("Enter the name: ")
lastname1 = input("Enter the last name: ")
name2 = input("Enter the name: ")
lastname2 = input("Enter the last name: ")
请不要使用列表作为变量名。列表是 python 中的 built-in 类型。
对于你的例子,你可以试试这个:
li = []
name1 = input("Enter the name: ")
lastname1 = input("Enter the last name: ")
li.append(name1 + ' ' + lastname1)
name2 = input("Enter the name: ")
lastname2 = input("Enter the last name: ")
li.append(name2 + ' ' + lastname2)
print(li)
# [John Conor, Michael Scott]
我想你要找的是这样的:
class Worker:
def __init__(self, name, lastname):
self.name = name
self.lastname = lastname
def __repr__(self):
return f'{self.name} {self.lastname}'
list_ = [] # note variable name
name1 = input("Enter the name: ")
lastname1 = input("Enter the last name: ")
list_.append(Worker(name1, lastname1))
name2 = input("Enter the name: ")
lastname2 = input("Enter the last name: ")
list_.append(Worker(name2, lastname2))
for worker in list_:
print(worker)
使用 lambda 函数执行此操作的最佳方法
#Devil
name1 = input("Enter the name: John ")
lastname1 = input("Enter the last name: Conor ")
name2 = input("Enter the name: Michael ")
lastname2 = input("Enter the last name: Scott ")
list_name = []
joint_name = lambda x, y : x + ' ' + y
list_name.append(joint_name(name1, lastname1))
list_name.append(joint_name(name2, lastname2))
#desire list
print("output :" , list_name)
#output : ['John Conor', 'Michael Scott']