合并列表中的字典并获取相等键的值集
Merge dicts from list with getting set of values for equal keys
我有机会用字典增强重写下面的代码吗？ （如果我命名正确，意思是 {k: v for k, v in ...}）
list_of_dicts = [{'a': 1}, {'b': 2}, {'b': 20, 'c': 3}, {'a': 10, 'b': 2}]
for k, v in [p for d in list_of_dicts for p in d.items()]:
d[k] = d.setdefault(k, set()) | {v}
确定为什么不 :)。但它嵌套在
位
import itertools
list_of_dicts = [{'a': 1}, {'b': 2}, {'b': 20, 'c': 3}, {'a': 10, 'b': 2}]
o = {k: {d[k] for d in list_of_dicts if k in d} for k in itertools.chain.from_iterable(list_of_dicts)}
print(o)
我有机会用字典增强重写下面的代码吗？ （如果我命名正确，意思是 {k: v for k, v in ...}）
list_of_dicts = [{'a': 1}, {'b': 2}, {'b': 20, 'c': 3}, {'a': 10, 'b': 2}]
for k, v in [p for d in list_of_dicts for p in d.items()]:
d[k] = d.setdefault(k, set()) | {v}
确定为什么不 :)。但它嵌套在
位import itertools
list_of_dicts = [{'a': 1}, {'b': 2}, {'b': 20, 'c': 3}, {'a': 10, 'b': 2}]
o = {k: {d[k] for d in list_of_dicts if k in d} for k in itertools.chain.from_iterable(list_of_dicts)}
print(o)