用 if 和 for 循环但没有得到预期的输出

Question

我正在编写一个 bash 脚本，如下所示，该脚本运行并给出如下输出。

输出：

4
3

但我的预期输出如下。有人可以指出我哪里出错了。提前致谢。

1
2
3
4

#!/bin/bash

region=('eu-central-1' 'us-east-1')
envs=('prod' 'stage')

for regions in "${region[@]}"; do

for env in "${envs[@]}"; do

if [ "${regions[*]}" == "eu-central" ] && [[ "${env[*]}" == "stage" ]]; then

echo 1

elif [ "${regions[*]}" == "eu-central" ] && [[ "${env[*]}" == "prod" ]]; then

echo 2

elif [ "${regions[*]}" == "us-east-1" ] && [[ "${env[*]}" == "stage" ]]; then

echo 3

elif [ "${regions[*]}" == "us-east-1" ] && [[ "${env[*]}" == "prod" ]]; then

echo 4

fi
done
done

Answer 1

1. 您正在与 eu-central 进行比较，但数组包含 eu-central-1
2. 您没有使用循环变量，而是关闭了 "${regions[*]}" 只需使用 "$regions"
3. 正确缩进您的脚本

---

应用以上内容得到：

#!/bin/bash

for regions in "${region[@]}"; do
    for env in "${envs[@]}"; do
        if [ "$regions" == "eu-central-1" ] && [[ "${env[*]}" == "stage" ]]; then
            echo 1
        elif [ "$regions" == "eu-central-1" ] && [[ "$env" == "prod" ]]; then
            echo 2
        elif [ "$regions" == "us-east-1" ] && [[ "$env" == "stage" ]]; then
            echo 3
        elif [ "$regions" == "us-east-1" ] && [[ "$env" == "prod" ]]; then
            echo 4
        fi
    done
done

---

2
1
4
3

---

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