如何按列分组而不考虑其他列和 return 所有对应行？

Question

我在 table AttendanceReg 中有员工的移动数据，例如：

EmpId	InPlace	InTime	OutTime
001	Plc01	10AM	11AM
002	Plc01	10AM	11AM
001	Plc02	11AM	12PM
002	Plc02	11AM	07PM
001	Plc01	12PM	06PM
003	Plc01	10AM	08PM

我想要一份员工报告第一进，最后进出它的位置。（应该取决于进出时间，而不是地点）

当我尝试聚合函数和分组依据时，它 returned:

Alter PROCEDURE UDP_AttReport @SelectDt Date
AS
select EmpID as ID,max(InPlace) as InPlace,min(InTime) as InTime Into #AttIN from AttendanceReg where cast(InTime as Date) = cast(@SelectDt as date) group by EmpID order by InTime desc 
select EmpID as ID, max(InPlace)as OutPlace,max(OutTime) as OutTime Into #AttOut from AttendanceReg where cast(InTime as Date) = cast(@SelectDt as date) group by EmpID order by OutTime desc 

SELECT #AttIN.ID,InPlace,InTime,OutPlace,OutTime Into #AttRep FROM #AttIN
RIGHT JOIN #AttOut
ON #AttIN.ID = #AttOut.ID
select ID,InPlace,InTime,OutPlace,OutTime from #AttRep Order by InTime asc

drop table #AttIN
drop table #AttOut
drop table #AttRep

Go

EmpId	InPlace	InTime	OutPlace	OutTime
001	Plc02	10AM	Plc02	06PM
002	Plc02	11AM	Plc02	07PM
003	Plc01	10AM	Plc01	08AM

但我期望的是

EmpId	InPlace	InTime	OutPlace	OutTime
001	Plc01	10AM	Plc01	06PM
002	Plc01	10AM	Plc02	07PM
003	Plc01	10AM	Plc01	08PM

我可以理解问题出在使用 Max(InPlace) 上（我在某处学到它可以在不按该列分组的情况下将 SQL 欺骗到 return 列）。

谢谢。

Answer 1

使用window函数row_number()通过EmpId

查找第一个和最后一个In或Out

with cte as
(
    select *, 
           rn = row_number() over (partition by EmpId order by InTime),
           rc = count(*) over (partition by EmpId)
    from   AttendanceReg
)
select EmpId, 
       InPlace  = max(case when rn = 1 then InPlace end),
       InTime   = max(case when rn = 1 then InTime end),
       OutPlace = max(case when rn = rn then InPlace end),
       OutTime  = max(case when rn = rn then OutTime end)
from   cte
group by EmpId

003 的 OutTime 是否有错误？应该是 08PM?

Answer 2

试试这个：

Select  a.EmpId, 
        a.InPlace, 
        a.InTime,
        b.Inplace as Outplace , 
        b.OutTime
From
    (Select EmpId, InPlace, InTime, ROW_NUMBER() over(partition by EmpId order by InTime) rn From test) a
inner join 
    (Select EmpId, InPlace, OutTime, ROW_NUMBER() over(partition by EmpId order by OutTime desc) rn From test) b
on 
    a.EmpId = b.EmpId
Where 
   a.rn = 1 
   and b.rn = 1

输出

如何按列分组而不考虑其他列和 return 所有对应行？

How to Group by a column irrespective of other column and return all corresponding rows?

sql

sql-server