CTE 中的 ParseError - Hive

Question

CTE 给出 parseError：ParseException 行 1:42 不匹配的输入 'as' 期望）在 'cust_xref_id' 附近

with table1 as 
(select 2020.cust_xref_id as 2020_cust, 2019.cust_xref_id as 2019_cust
from dea.sp_2020_us as 2020
left join dea.sp_2019_us as 2019
on 2020.cust_xref_id = 2019.cust_xref_id)
select count(distinct(*))
from tabel1
where 2019_cust is not null;

想不通哪里错了。如有任何帮助，我们将不胜感激！

Answer 1

如果列名不是以字符串开头，我们必须用反引号将名称括起来 (2020_cust`).

CTE 中的 ParseError - Hive

ParseError in CTE - Hive

hive

common-table-expression