如何提取与XML.extract同级的标签？

Question

通过此查询，我获取了标记 ROW 内的所有内容。但我想把所有东西都带上标签 .

select xmltype(
  '<?xml version="1.0"?> 
  <ROWSET> 
    <ROW>
      <PERSON_NUMBER>1000142</PERSON_NUMBER>
      <LOAN_1>25000</LOAN_1>
    </ROW> 
    <ROW>
      <PERSON_NUMBER>1000142</PERSON_NUMBER>
      <LOAN_1>25000</LOAN_1>
    </ROW> 
  </ROWSET>'
).extract( '/ROWSET/ROW' ) .getstringval() p#
from dual;

我可以select子标签

select xmltype(
  '<?xml version="1.0"?> 
  <ROWSET> 
    <ROW>
      <PERSON_NUMBER>1000142</PERSON_NUMBER>
      <LOAN_1>25000</LOAN_1>
      <field_without_interest>f</field_without_interest>
    </ROW> 
    <ROW>
      <PERSON_NUMBER>1000142</PERSON_NUMBER>
      <LOAN_1>25000</LOAN_1>
    </ROW> 
  </ROWSET>'
).extract( '/ROWSET/ROW/PERSON_NUMBER' ) .getstringval() p#
from dual;

但我select只关注我感兴趣的一半标签。

有没有办法写extract( '/ROWSET/ROW/PERSON_NUMBER' AND '/ROWSET/ROW/LOAN_1' ) 要么 extract( '/ROWSET/ROW/ except'/ROWSET/ROW/field_without_interest' )

code

Answer 1

您可以使用 XMLQUERY 和 FLOWR。

如果您只想要第一个 ROW 那么：

SELECT XMLQUERY(
         'copy $NEWHTML := /ROWSET/ROW[1]
         modify (
           for $i in $NEWHTML/field_without_interest
           return delete node $i
         )
         return $NEWHTML/*'
         PASSING xmltype(
  '<?xml version="1.0"?> 
  <ROWSET> 
    <ROW>
      <PERSON_NUMBER>1000142</PERSON_NUMBER>
      <LOAN_1>25000</LOAN_1>
      <field_without_interest>f</field_without_interest>
    </ROW> 
    <ROW>
      <PERSON_NUMBER>1000142</PERSON_NUMBER>
      <LOAN_1>25000</LOAN_1>
    </ROW> 
  </ROWSET>'
)
         RETURNING CONTENT
       ).getStringVal() AS interested_elements
FROM   DUAL;

输出：

INTERESTED_ELEMENTS

<PERSON_NUMBER>1000142</PERSON_NUMBER><LOAN_1>25000</LOAN_1>

或者，如果您想要整个 ROWSET，您可以使用：

SELECT XMLQUERY(
         'copy $NEWHTML := .
         modify (
           for $i in $NEWHTML/ROWSET/ROW/field_without_interest
           return delete node $i
         )
         return $NEWHTML'
         PASSING xmltype(
  '<?xml version="1.0"?> 
  <ROWSET> 
    <ROW>
      <PERSON_NUMBER>1000142</PERSON_NUMBER>
      <LOAN_1>25000</LOAN_1>
      <field_without_interest>f</field_without_interest>
    </ROW> 
    <ROW>
      <PERSON_NUMBER>1000142</PERSON_NUMBER>
      <LOAN_1>25000</LOAN_1>
    </ROW> 
  </ROWSET>'
)
         RETURNING CONTENT
       ).getStringVal() AS interested_elements
FROM   DUAL;

输出：

INTERESTED_ELEMENTS

<?xml version="1.0"?><ROWSET><ROW><PERSON_NUMBER>1000142</PERSON_NUMBER><LOAN_1>25000</LOAN_1></ROW><ROW><PERSON_NUMBER>1000142</PERSON_NUMBER><LOAN_1>25000</LOAN_1></ROW></ROWSET>

db<>fiddle here

如何提取与XML.extract同级的标签？

How to extract tags at the same level with XML.extract?

sql

xml

oracle