从 JOINED 表中获取合计数量
Get aggregate quantity from JOINED tables
我的数据库中有以下两个 table
inventory_transactions table
id | date_created | company_id | product_id | quantity | amount | is_verified | buy_or_sell_to | transaction_type | parent_tx | invoice_id | order_id | transaction_comment
----+----------------------------+------------+------------+----------+--------+-------------+----------------+------------------+-----------+------------+----------+---------------------
1 | 2022-04-25 10:42:00.627495 | 20 | 100 | 23 | 7659 | t | | BUY | | 1 | |
2 | 2022-04-25 10:48:48.02342 | 21 | 2 | 10 | 100 | t | | BUY | | 2 | |
3 | 2022-04-25 11:00:11.624176 | 21 | 7 | 10 | 100 | t | | BUY | | 3 | |
4 | 2022-04-25 11:08:14.607117 | 23 | 1 | 11 | 1210 | t | | BUY | | 4 | |
5 | 2022-04-25 11:13:24.084845 | 23 | 28 | 16 | 2560 | t | | BUY | | 5 | |
6 | 2022-04-25 11:26:56.338881 | 23 | 28 | 15 | 3525 | t | 5 | BUY | | 6 | 1 |
7 | 2022-04-25 11:26:56.340112 | 5 | 28 | 15 | 3525 | t | 23 | SELL | 6 | 6 | 1 |
8 | 2022-04-25 11:30:08.529288 | 23 | 30 | 65 | 15925 | t | 5 | BUY | | 7 | 2 |
9 | 2022-04-25 11:30:08.531005 | 5 | 30 | 65 | 15925 | t | 23 | SELL | 8 | 7 | 2 |
14 | 2022-04-25 12:28:51.658902 | 23 | 28 | 235 | 55225 | t | 5 | BUY | | 11 | 5 |
15 | 2022-04-25 12:28:51.660478 | 5 | 28 | 235 | 55225 | t | 23 | SELL | 14 | 11 | 5 |
20 | 2022-04-25 13:01:31.091524 | 20 | 4 | 4 | 176 | t | | BUY | | 15 | |
10 | 2022-04-25 11:50:48.4519 | 21 | 38 | 1 | 10 | t | | BUY | | 8 | |
11 | 2022-04-25 11:50:48.454118 | 21 | 36 | 1 | 10 | t | | BUY | | 8 | |
12 | 2022-04-25 11:52:19.827671 | 21 | 29 | 1 | 10 | t | | BUY | | 9 | |
13 | 2022-04-25 11:53:16.699881 | 21 | 74 | 1 | 10 | t | | BUY | | 10 | |
16 | 2022-04-25 12:37:39.739125 | 20 | 1 | 228 | 58824 | t | | BUY | | 12 | |
17 | 2022-04-25 12:37:39.741106 | 20 | 3 | 228 | 58824 | t | | BUY | | 12 | |
18 | 2022-04-25 12:49:09.922686 | 21 | 41 | 10 | 1000 | t | | BUY | | 13 | |
19 | 2022-04-25 12:55:11.986451 | 20 | 5 | 22 | 484 | t | | BUY | | 14 | |
注意 inventory_transactions table 中的每笔交易都记录了两次，其中 company_id 和 buy_or_sell_to 交换了第二次行和 transaction_type 买入或卖出保留。 （类似于会计中日记帐的处理方式）。
db# select * from inventory_transactions where buy_or_sell_to is not Null order by date_created limit 50;
id | date_created | company_id | product_id | quantity | amount | is_verified | buy_or_sell_to | transaction_type | parent_tx | invoice_id | order_id | transaction_comment
----+----------------------------+------------+------------+----------+--------+-------------+----------------+------------------+-----------+------------+----------+---------------------
6 | 2022-04-25 11:26:56.338881 | 23 | 28 | 15 | 3525 | t | 5 | BUY | | 6 | 1 |
7 | 2022-04-25 11:26:56.340112 | 5 | 28 | 15 | 3525 | t | 23 | SELL | 6 | 6 | 1 |
8 | 2022-04-25 11:30:08.529288 | 23 | 30 | 65 | 15925 | t | 5 | BUY | | 7 | 2 |
9 | 2022-04-25 11:30:08.531005 | 5 | 30 | 65 | 15925 | t | 23 | SELL | 8 | 7 | 2 |
companies table（将此视为用户 table，在我的项目中所有用户都是公司）
id | company_type | gstin | name | phone_no | address | pincode | is_hymbee_verified | is_active | district_id | pancard_no
----+--------------+-----------------+-------------+------------+---------+---------+--------------------+-----------+-------------+------------
26 | RETAILER | XXXXXXXXXXXXXXX | ACD LLC | 12345%7898 | AQWSAQW | 319401 | | | 11 | AQWSDERFVV
27 | DISTRIBUTOR | XXXXXXXXXXXXXXX | CDF LLC | 123XX7898 | AGWSAQW | 319201 | | | 13 | AQWSDERFVV
28 | RETAILER | XXXXXXXXXXXXXXX | !@# LLC | 1234!67XX9 | AQCCAQW | 319101 | | | 16 | AQWSDERFVV
29 | COMPANY | XXXXXXXXXXXXXXX | ZAZ LLC | 123456S898 | AQWQQQW | 319001 | | | 19 | AQWSDERFVV
问题陈述
我尝试编写的查询将获取仅售给 RETAILER 用户和 DISTRIBUTORS 用户 RETAILER 或 [=23= 用户的数量].
例如，如果一个用户是 RETAILER，我们需要计算这个 RETAILER 已经卖给其他 RETAILER 或 [=23= 的用户的数量]s.
换句话说，对于 companies table 中的所有行，检查 company 是否属于 company_type、RETAILER 或 DISTRIBUTOR 并从 inventory_transactions table，检查 quantity 一个 partiuclar RETAILER 或 DISTRIBUTOR 卖给其他 RETAILER 和 [=23] 的数量=]s
我对 SQL 有非常基本的了解，目前只了解了：
select Seller.id as Seller_ROW, Buyer.id as Buyer_row, Seller.company_id, Buyer.buy_or_sell_to, Seller.company_type as Seller_Type, Buyer.company_type as Buyer_Type, Seller.quantity, Buyer.quantity
FROM
(select t.id, t.company_id, t.quantity, c.company_type
from inventory_transactions as t
join companies as c on c.id = t.company_id
where c.company_type = 'RETAILER' or company_type = 'DISTRIBUTOR'
) as Seller
JOIN
(select t.id, t.buy_or_sell_to, t.quantity, c.company_type
from inventory_transactions as t
join companies as c on c.id = t.buy_or_sell_to
where c.company_type = 'RETAILER' or company_type = 'DISTRIBUTOR') as Buyer on Seller.id = Buyer.id
产出
seller_row | buyer_row | company_id | buy_or_sell_to | seller_type | buyer_type | quantity | quantity
------------+-----------+------------+----------------+-------------+-------------+----------+----------
25 | 25 | 22 | 25 | RETAILER | DISTRIBUTOR | 1 | 1
26 | 26 | 25 | 22 | DISTRIBUTOR | RETAILER | 1 | 1
31 | 31 | 37 | 43 | DISTRIBUTOR | RETAILER | 10 | 10
32 | 32 | 43 | 37 | RETAILER | DISTRIBUTOR | 10 | 10
33 | 33 | 21 | 43 | DISTRIBUTOR | RETAILER | 1 | 1
34 | 34 | 43 | 21 | RETAILER | DISTRIBUTOR | 1 | 1
35 | 35 | 21 | 49 | DISTRIBUTOR | RETAILER | 1 | 1
36 | 36 | 49 | 21 | RETAILER | DISTRIBUTOR | 1 | 1
37 | 37 | 21 | 51 | DISTRIBUTOR | RETAILER | 1 | 1
38 | 38 | 51 | 21 | RETAILER | DISTRIBUTOR | 1 | 1
结果 table 中有重复的行，所以我无法执行 SUM()。
预期结果
SELLER.company_id | SELLER.company_name | SELLER.company_type | QUANTITY | BUYER.company_type
26 | XYZ Retail Co. | RETAILER | 14 | RETAILER
26 | XYZ Retail Co. | RETAILER | 1 | DISTRIBUTOR
27 | ACD Distributions | DISTRIBUTOR | 0 | RETAILER
27 | ACD Distributions | DISTRIBUTOR | 10 | DISTRIBUTOR
此答案假设每个销售都表示为 inventory_transactions 中的两行，这样可以通过仅使用一个 transaction_type 来避免重复，因此我们将过滤 [=13] =] 交易。
SELECT t.company_id AS seller_company_id
, s.company_name AS seller_company_name
, s.company_type AS seller_company_type
, SUM(t.quantity) AS quantity
, b.company_type AS buyer_company_type
FROM inventory_transactions AS t
INNER JOIN companies AS s
ON s.id = t.company_id
INNER JOIN companies AS b
ON b.id = buy_or_sell_to
WHERE t.transaction_type = 'SELL'
AND s.company_type IN ('RETAILER','DISTRIBUTOR')
AND b.company_type IN ('RETAILER','DISTRIBUTOR')
GROUP BY t.company_id, s.company_name, s.company_type, b.company_type
ORDER BY seller_company_id, seller_company_name, seller_company_type, buyer_company_type
;
我的数据库中有以下两个 table
inventory_transactions table
id | date_created | company_id | product_id | quantity | amount | is_verified | buy_or_sell_to | transaction_type | parent_tx | invoice_id | order_id | transaction_comment
----+----------------------------+------------+------------+----------+--------+-------------+----------------+------------------+-----------+------------+----------+---------------------
1 | 2022-04-25 10:42:00.627495 | 20 | 100 | 23 | 7659 | t | | BUY | | 1 | |
2 | 2022-04-25 10:48:48.02342 | 21 | 2 | 10 | 100 | t | | BUY | | 2 | |
3 | 2022-04-25 11:00:11.624176 | 21 | 7 | 10 | 100 | t | | BUY | | 3 | |
4 | 2022-04-25 11:08:14.607117 | 23 | 1 | 11 | 1210 | t | | BUY | | 4 | |
5 | 2022-04-25 11:13:24.084845 | 23 | 28 | 16 | 2560 | t | | BUY | | 5 | |
6 | 2022-04-25 11:26:56.338881 | 23 | 28 | 15 | 3525 | t | 5 | BUY | | 6 | 1 |
7 | 2022-04-25 11:26:56.340112 | 5 | 28 | 15 | 3525 | t | 23 | SELL | 6 | 6 | 1 |
8 | 2022-04-25 11:30:08.529288 | 23 | 30 | 65 | 15925 | t | 5 | BUY | | 7 | 2 |
9 | 2022-04-25 11:30:08.531005 | 5 | 30 | 65 | 15925 | t | 23 | SELL | 8 | 7 | 2 |
14 | 2022-04-25 12:28:51.658902 | 23 | 28 | 235 | 55225 | t | 5 | BUY | | 11 | 5 |
15 | 2022-04-25 12:28:51.660478 | 5 | 28 | 235 | 55225 | t | 23 | SELL | 14 | 11 | 5 |
20 | 2022-04-25 13:01:31.091524 | 20 | 4 | 4 | 176 | t | | BUY | | 15 | |
10 | 2022-04-25 11:50:48.4519 | 21 | 38 | 1 | 10 | t | | BUY | | 8 | |
11 | 2022-04-25 11:50:48.454118 | 21 | 36 | 1 | 10 | t | | BUY | | 8 | |
12 | 2022-04-25 11:52:19.827671 | 21 | 29 | 1 | 10 | t | | BUY | | 9 | |
13 | 2022-04-25 11:53:16.699881 | 21 | 74 | 1 | 10 | t | | BUY | | 10 | |
16 | 2022-04-25 12:37:39.739125 | 20 | 1 | 228 | 58824 | t | | BUY | | 12 | |
17 | 2022-04-25 12:37:39.741106 | 20 | 3 | 228 | 58824 | t | | BUY | | 12 | |
18 | 2022-04-25 12:49:09.922686 | 21 | 41 | 10 | 1000 | t | | BUY | | 13 | |
19 | 2022-04-25 12:55:11.986451 | 20 | 5 | 22 | 484 | t | | BUY | | 14 | |
注意 inventory_transactions table 中的每笔交易都记录了两次，其中 company_id 和 buy_or_sell_to 交换了第二次行和 transaction_type 买入或卖出保留。 （类似于会计中日记帐的处理方式）。
db# select * from inventory_transactions where buy_or_sell_to is not Null order by date_created limit 50;
id | date_created | company_id | product_id | quantity | amount | is_verified | buy_or_sell_to | transaction_type | parent_tx | invoice_id | order_id | transaction_comment
----+----------------------------+------------+------------+----------+--------+-------------+----------------+------------------+-----------+------------+----------+---------------------
6 | 2022-04-25 11:26:56.338881 | 23 | 28 | 15 | 3525 | t | 5 | BUY | | 6 | 1 |
7 | 2022-04-25 11:26:56.340112 | 5 | 28 | 15 | 3525 | t | 23 | SELL | 6 | 6 | 1 |
8 | 2022-04-25 11:30:08.529288 | 23 | 30 | 65 | 15925 | t | 5 | BUY | | 7 | 2 |
9 | 2022-04-25 11:30:08.531005 | 5 | 30 | 65 | 15925 | t | 23 | SELL | 8 | 7 | 2 |
companies table（将此视为用户 table，在我的项目中所有用户都是公司）
id | company_type | gstin | name | phone_no | address | pincode | is_hymbee_verified | is_active | district_id | pancard_no
----+--------------+-----------------+-------------+------------+---------+---------+--------------------+-----------+-------------+------------
26 | RETAILER | XXXXXXXXXXXXXXX | ACD LLC | 12345%7898 | AQWSAQW | 319401 | | | 11 | AQWSDERFVV
27 | DISTRIBUTOR | XXXXXXXXXXXXXXX | CDF LLC | 123XX7898 | AGWSAQW | 319201 | | | 13 | AQWSDERFVV
28 | RETAILER | XXXXXXXXXXXXXXX | !@# LLC | 1234!67XX9 | AQCCAQW | 319101 | | | 16 | AQWSDERFVV
29 | COMPANY | XXXXXXXXXXXXXXX | ZAZ LLC | 123456S898 | AQWQQQW | 319001 | | | 19 | AQWSDERFVV
问题陈述
我尝试编写的查询将获取仅售给 RETAILER 用户和 DISTRIBUTORS 用户 RETAILER 或 [=23= 用户的数量].
例如，如果一个用户是 RETAILER，我们需要计算这个 RETAILER 已经卖给其他 RETAILER 或 [=23= 的用户的数量]s.
换句话说，对于 companies table 中的所有行，检查 company 是否属于 company_type、RETAILER 或 DISTRIBUTOR 并从 inventory_transactions table，检查 quantity 一个 partiuclar RETAILER 或 DISTRIBUTOR 卖给其他 RETAILER 和 [=23] 的数量=]s
我对 SQL 有非常基本的了解，目前只了解了：
select Seller.id as Seller_ROW, Buyer.id as Buyer_row, Seller.company_id, Buyer.buy_or_sell_to, Seller.company_type as Seller_Type, Buyer.company_type as Buyer_Type, Seller.quantity, Buyer.quantity
FROM
(select t.id, t.company_id, t.quantity, c.company_type
from inventory_transactions as t
join companies as c on c.id = t.company_id
where c.company_type = 'RETAILER' or company_type = 'DISTRIBUTOR'
) as Seller
JOIN
(select t.id, t.buy_or_sell_to, t.quantity, c.company_type
from inventory_transactions as t
join companies as c on c.id = t.buy_or_sell_to
where c.company_type = 'RETAILER' or company_type = 'DISTRIBUTOR') as Buyer on Seller.id = Buyer.id
产出
seller_row | buyer_row | company_id | buy_or_sell_to | seller_type | buyer_type | quantity | quantity
------------+-----------+------------+----------------+-------------+-------------+----------+----------
25 | 25 | 22 | 25 | RETAILER | DISTRIBUTOR | 1 | 1
26 | 26 | 25 | 22 | DISTRIBUTOR | RETAILER | 1 | 1
31 | 31 | 37 | 43 | DISTRIBUTOR | RETAILER | 10 | 10
32 | 32 | 43 | 37 | RETAILER | DISTRIBUTOR | 10 | 10
33 | 33 | 21 | 43 | DISTRIBUTOR | RETAILER | 1 | 1
34 | 34 | 43 | 21 | RETAILER | DISTRIBUTOR | 1 | 1
35 | 35 | 21 | 49 | DISTRIBUTOR | RETAILER | 1 | 1
36 | 36 | 49 | 21 | RETAILER | DISTRIBUTOR | 1 | 1
37 | 37 | 21 | 51 | DISTRIBUTOR | RETAILER | 1 | 1
38 | 38 | 51 | 21 | RETAILER | DISTRIBUTOR | 1 | 1
结果 table 中有重复的行，所以我无法执行 SUM()。
预期结果
SELLER.company_id | SELLER.company_name | SELLER.company_type | QUANTITY | BUYER.company_type
26 | XYZ Retail Co. | RETAILER | 14 | RETAILER
26 | XYZ Retail Co. | RETAILER | 1 | DISTRIBUTOR
27 | ACD Distributions | DISTRIBUTOR | 0 | RETAILER
27 | ACD Distributions | DISTRIBUTOR | 10 | DISTRIBUTOR
此答案假设每个销售都表示为 inventory_transactions 中的两行，这样可以通过仅使用一个 transaction_type 来避免重复，因此我们将过滤 [=13] =] 交易。
SELECT t.company_id AS seller_company_id
, s.company_name AS seller_company_name
, s.company_type AS seller_company_type
, SUM(t.quantity) AS quantity
, b.company_type AS buyer_company_type
FROM inventory_transactions AS t
INNER JOIN companies AS s
ON s.id = t.company_id
INNER JOIN companies AS b
ON b.id = buy_or_sell_to
WHERE t.transaction_type = 'SELL'
AND s.company_type IN ('RETAILER','DISTRIBUTOR')
AND b.company_type IN ('RETAILER','DISTRIBUTOR')
GROUP BY t.company_id, s.company_name, s.company_type, b.company_type
ORDER BY seller_company_id, seller_company_name, seller_company_type, buyer_company_type
;