如何从字符串列表中有条件地删除子字符串？

Question

我有以下字符串列表：

my_list1 = [' If the display is not working ', "<xxx - tutorial section>", "tutorial section", ' display message appears. ']

my_list2 = [' If the display is not working ', "tutorial section", "<xxx - tutorial section>", ' display message appears. ']

如何识别等于 - 之后或之前被 < 和 > 符号包围的子字符串的字符串。在我的示例中，这是 tutorial section。我想删除此字符串以获得以下结果：

my_list1_ed = [' If the display is not working ', "<xxx - tutorial section>", ' display message appears. ']

my_list2_ed = [' If the display is not working ', "<xxx - tutorial section>", ' display message appears. ']

如果列表不包含此类重复项，则不应执行任何操作。我该如何实现这个逻辑？

我的尝试：

final_list = []
lists = my_list1 + my_list2
for i, v in enumerate(lists):
   if (v not in lists[i-1]) or (v not in lists[i+1]):
       final_list.append(v)

我得到的结果（仍然存在重复）：

[' If the display is not working ',
 '<xxx - tutorial section>',
 'tutorial section',
 ' display message appears. ',
 ' If the display is not working ',
 'tutorial section',
 '<xxx - tutorial section>',
 ' display message appears. ']

Answer 1

稍微修改一下代码，看看是否有帮助。

final_list = []
lists = my_list1 + my_list2

for i, v in enumerate(lists):
    if i == 0:
        if v not in lists[i+1]:
            final_list.append(v)
    elif i == len(lists) - 1:
        if v not in lists[i-1]:
            final_list.append(v)
    else:
        if (v not in lists[i-1]) and (v not in lists[i+1]):
            final_list.append(v)

print(final_list)

输出：[' If the display is not working ', '<xxx - tutorial section>', ' display message appears. ', ' If the display is not working ', '<xxx - tutorial section>', ' display message appears. ']

Answer 2

以下是我的操作方法。

my_list1 = [' If the display is not working ', "<xxx - tutorial section>", "tutorial section", ' display message appears. ']

my_list2 = [' If the display is not working ', "tutorial section", "<xxx - tutorial section>", ' display message appears. ']

all_l = []
new_list1 = []
new_list2 = []
matches = ['-','<','>']
for i in range(len(my_list1)):
    if any(x in my_list1[i] for x in matches):
       nl1 = [r for r in my_list1 if not r in my_list1[i] or r == my_list1[i]]
       new_list1 = nl1
    if any(x in my_list2[i] for x in matches):
       nl2 = [r for r in my_list2 if not r in my_list2[i] or r == my_list2[i]]
       new_list2 = nl2
  
print(new_list1)
print(new_list2)

输出：

[' If the display is not working ', '<xxx - tutorial section>', ' display message appears. ']
[' If the display is not working ', '<xxx - tutorial section>', ' display message appears. ']

如何从字符串列表中有条件地删除子字符串？

How to remove a substring conditionally from a list of strings?

python

string