sed 将 url 中的 * 替换为 json 文件中的文本

Question

我想更改 json 文件中的键值

示例：

"House":"sample.house.city"

需要将“示例”一词更改为其他名称。

我可以这样做：

sed -i 's|sample.house.city|town-home.house.city|g' file.json

但不能保证“样本”每次都相同。

我试过：

sed -i 's|*.house.city|town-home.house.city|g' file.json

但它没有改变。

也尝试过：

sed -i 's|"*.house.city"|"town-home.house.city"|g' file.json

但结果是这样的：

"sample"town-home.house.city"

关于如何正确执行此操作的任何建议？

Answer 1

要匹配任何单词，可以使用[[:alnum:]_]* (POSIX BRE) / [[:alnum:]_]+ (POSIX ERE):

sed -i 's|[[:alnum:]_]*\.house\.city|townhome.house.city|g' file.json

查看 online demo:

#!/bin/bash
s='"House":"sample.house.city"'
sed 's|[[:alnum:]_]*\.house\.city|townhome.house.city|g' <<< "$s"

输出：

"House":"townhome.house.city"

请注意，您还需要转义用于匹配文字点的点。

Answer 2

Explanation

1st Capturing Group (\w+)

\w matches any word character (equivalent to [a-zA-Z0-9_])

+ matches the previous token between one and unlimited times, as many times as possible, giving back as needed (greedy)

2nd Capturing Group (.house.city)

\. matches the character .

house matches the characters house literally (case sensitive)

\. matches the character .

city matches the characters city literally (case sensitive)

Global pattern flags

g modifier: global. All matches (don't return after first match)

replace with the 2nd Captured Group (.house.city)

$ sed -E 's/(\w+)(\.house\.city)/town-home/g' <<< '"House":"sample.house.city"'

"House":"town-home.house.city"

$ sed -iE 's/(\w+)(\.house\.city)/town-home/g' file.json

sed 将 url 中的 * 替换为 json 文件中的文本

sed replace * in url with text in json file

json

bash

unix

sed

Explanation